Answer:
g and g
Step-by-step explanation:
just did
The standard form for the equation of a circle is :
<span><span> (x−h)^2</span>+<span>(y−k)^2</span>=r2</span><span> ----------- EQ(1)
</span> where handk are the x and y coordinates of the center of the circle and r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :
((2+(8))/2,(-5+(-9))/2)=(5,-7)
So the point (5,-7) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(2−(5))^2+(-5−(-7))^2=9+4=13
⇒r=√13
Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :
(x-5)^2+(y+7)^2=13
So to do that, find the point of S then transform
in (x,y) form
we see that the point 'S' is 1 unit to the right and 2 units up therefor
the point is (1,2)
so we jsut apply the thingy translation to is
x=1
y=2
x+2=1+2=3
y-1=2-1=1
the new point is (3,1)
Answer:

Step-by-step explanation:
Given:
Slope (m) = ⁴/3
Point on the line = (x, y) = (3, 2)
Required:
Write the equation in slope-intercept form which is y = mx + b
Solution:
Since we know the slope(m), we need to find the y-intercept (b).
This, substitute (x, y) = (3, 2) and m = ⁴/3 into y = mx + b, and solve for b. Thus:
2 = ⁴/3(3) + b
2 = 4 + b
2 - 4 = b
-2 = b
b = -2
To write the equation, substitute m = ⁴/3 and b = -2 into y = mx + b

Answer:
x= -9
Step-by-step explanation:
-x+3=2(x+15)
-x+3=2x+30
-x-2x+3=30-3
-3x=30-3
-3x=27
x= -9