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Dennis_Churaev [7]
3 years ago
8

A student is assessing the correlation between the number of hours a plant receives sunlight and the height to which it grows. [

please help ASAP]
The table shows the data: Number of hours of sunlight (x) 0 1 2 3 4 5 6 7 8 9 Height of plant in cm (y) 4 7 10 13 16 19 22 25 28 31

Part A: Is there any correlation between the number of hours of sunlight that a plant receives and the height to which it grows? Justify your answer.

Part B: Write a function that best fits the data.

Part C: What does the slope and y-intercept of the plot indicate about the plant?

Mathematics
1 answer:
BigorU [14]3 years ago
4 0

Answer:

i only understand part A:

a) Yes, the more time the plant spend in sunlight, the taller it grows. for example, the plant that spend no time in the sun only grows to 4cm while the plant that spent 9 hours in the sun grew to 31

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The sum of 2 numbers is 45. The larger number is 17 more than the smaller number. What are the numbers
gayaneshka [121]

Answer:

the numbers are 31 and 14

Step-by-step explanation:

since the larger number is 17 more than the smaller number,

larger number= x

smaller number= x-17

x-17+x=45

2x=45+17

2x=62

x=31

x-17=31-17

3 0
3 years ago
Translate into a equation. one subtracted from two times a number is -45.​
sleet_krkn [62]

Answer:

2x - 1 = -45.

Step-by-step explanation:

2x - 1 = -45 is the required equation.

x is the number.

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A cylinder with a base diameter of x units has a volume
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2nd opinion that’s your answer
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Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n
konstantin123 [22]

Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

T = \frac{(n-1) S^2}{\sigma^2}

And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

P(S^2 > 9.1)

And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

P(3.462 < S^2

If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0
3 years ago
Х у
erica [24]

Answer:

A. Linear

Step-by-step explanation:

As the x value goes up by 1, the y value goes up by 3 each time

8 0
2 years ago
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