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3 years ago

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What are the dimensions of a rectangular tract of land when its perimeter is 66 kilometers and its area is 260 square kilometers

? (enter the lengths of the sides as a comma-separated list.)?

1 answer:

Nikitich [7]3 years ago

7 0

The longer sides are 20 kilometers, and the shorter sides are 13 kilometers.
(Length times width equals 260, and 20 times 2 plus 13 times 2 is 66.)

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Please help me with this question and thank you for your help

Volgvan

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3 years ago

Read 2 more answers

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

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3 years ago

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tino4ka555 [31]

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~Zoe

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3 years ago

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3 years ago

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Nuetrik [128]

nswer:

B C = 24

Explanation:

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A C = A B

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3 years ago