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Sergeeva-Olga [200]
3 years ago
7

Twelve pens and 16 pencils will be placed in bags with equal number of each item.

Mathematics
2 answers:
Alla [95]3 years ago
5 0
You divide 16 into 12 and get 1.3 repeating
frozen [14]3 years ago
5 0
Divide 16 into 12 and you’ll get 1.3
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Which of the following is equivalent to (Cd) to the fifth power
Rina8888 [55]

Answer:

The 3rd option is correct.

Step-by-step explanation:

This is because of an exponent rule that goes:

(xy)^z = x^z(y^z)

The whole thing gets raised to the power. Therefore only the 3rd one works (ps. if you can mark as brainliest that would be amazing, but if not that's fine)

5 0
2 years ago
La pregunta en la imagen
dusya [7]

Answer:

216mx meters

Step-by-step explanation:

m is in minutes so convert it in hours = 60m hrs

Speed is in metres per second, convert it in kilometers per hour= 18x/5

Now we’ve time and speed, put it in the formula

Distance = speed x time

= 18x/5 x 60m

= 216mx meters

Hope it helps

6 0
2 years ago
Help? I’ll give brainliest
Vaselesa [24]

9514 1404 393

Answer:

  10,466.7 in^3

Step-by-step explanation:

The volume of a cone is given by ...

  V = (1/3)πr^2·h

where r is the radius and h is the height. Using your numbers, we have ...

  V = (1/3)(3.14)(20 in)^2·(25 in) = 10,466.7 in^3

_____

A more accurate value of π will give a different result.

4 0
2 years ago
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) greater than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) equal to 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) between 10 and 15, inclusively

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
3 years ago
K(n)=n^3-3n; Find k(-5)
kozerog [31]

Answer:

The answer to your question is:    k(-5) = -115

Step-by-step explanation:

Function       k(n) = n³ - 3n      find k(-5)

                    k(-5) = (-5)³ - 3(-5)             substitution

                    k(-5) = -125 + 15                simplify

                    k(-5) = -115

5 0
3 years ago
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