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cupoosta [38]
3 years ago
9

Find the circumference of the circle in terms of π.

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
4 0

Answer:

  • C) 12π cm

Step-by-step explanation:

<u>Circumference formula:</u>

  • C = 2πr

Given r = 6 cm

<u>Circumference is:</u>

  • C = 2π*6 cm = 12π cm

Correct choice is C

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6 x - 2 [ x + 2 ] &gt; 2 - 3 [ x + 3]<br> could u show me step by step on how to do thiz
Dafna11 [192]

Answer:

x > - 3/7

Step-by-step explanation:

6x - 2x - 4 > 2 - 3 (x + 3)

6x - 2x - 4 > 2 - 3x - 9

4x - 4 > 2 - 3x - 9

4x - 4 > - 7 - 3x

4x - 4 + 3x > - 7

7x > - 7 + 4

7x > - 3

8 0
3 years ago
GUYS PLEASE HELP! AND SOLVE THIS WITH ME!
tino4ka555 [31]

Answer:

Step-by-step explanation:

* 33/100 = .3(bar)

* 23/50 =.46

* 6/8 = .75

* 1/3 = .3(bar)

* 7/10 =.7

* 21/81 = .26

* 3/16 = .1875

* 7/20 =.35

5 0
3 years ago
A steel company sells 48 tons of steel each year.
ddd [48]

Answer:

16 tons

Step-by-step explanation:

To solve the first step is to change years to months because the time periods are in different units. There are 12 months in 1 year. This means that the company sells 48 tons over 12 months. 4 months is the equivalent of 1/3 of 12 months. This means that we can find the amount sold in 4 months by dividing 48 by 3. 48/3 is 16. Thus, the steel company sells 16 tons in 4 months.

Another way to find the answer is to find the unit rate. The unit rate is how many tons are sold in 1 month. Find this by dividing 48 by 12 because this represents the sales of 1 month. 48/12=4, this means that in 1 month, 4 tons of steel are sold. Next, multiply 4 times 4 to find the amount of steel sold in 4 months. 4 times 4 also gives you the same answer of 16.

6 0
3 years ago
Write an equation in point-slope form of the line through the point (−1, 2) and with slope m = 2.
Katen [24]

Answer:

D. y - 2 = 2(x + 1)

Step-by-step explanation:

<h3>y - y₁ = m (x - x₁)</h3>

y - 2 = 2 (x - (-1))

y - 2 = 2 (x + 1)

<h3>#CMIIW</h3>
3 0
3 years ago
An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t
EleoNora [17]

Answer:

Rachel

Step-by-step explanation:

We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.  

That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that

mean - x*s = t

For Rachel we have

11 - x*3 = 8, so x = 1.  

Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class

For Kenji we have

9 - x*2 = 8.5, so x = 0.25

Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class

For Nedda we have

7 - x*4 = 8, so x = 0.25

Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.

As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.

8 0
3 years ago
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