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sergey [27]
4 years ago
9

3.) Identify all integers. a. 725 d. 50 e. 10.2 C. 806

Mathematics
2 answers:
NeTakaya4 years ago
8 0

Answer:

A, B, C

Step-by-step explanation:

An integer is a whole number (so not a fraction)

Tanya [424]4 years ago
4 0
E is the correct option to your question
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Find the area of the regular hexagon if the radius of a circle inscribed in the hexagon is 10√3
sleet_krkn [62]

Answer:

  • D. 600√3  

Step-by-step explanation:

<u />

<u>Refer to your previous question: </u>

  • brainly.com/question/22624022

Radius of the inscribed circle is the apothem of the hexagon.

Apothem (a) and half of the side (s) make a 30-60-90 right triangle.

<u>The ratio of the legs, as per property of 30-60-90 triangle:</u>

  • s : a = 1 : √3 ⇒ s : 10√3 = 1 : √3 ⇒ s = 10

Half the side is s = 10 units, then side of the hexagon is 20 units.

<u>The area of the hexagon:</u>

  • A = 1/2Pa, P- perimeter, a- apothem
  • A = 1/2(6*20)*(10√3) = 600√3

Correct choice is D

8 0
3 years ago
What is the value of ​
dimulka [17.4K]

Answer:

-4

Step-by-step explanation:

its -4 I hope you have received

7 0
3 years ago
Read 2 more answers
What is the x coordinate of the solution to the system of equations?
igomit [66]

Answer:

The x coordinate of the solution to the system of equations is 8

Step-by-step explanation:

We need to find the x coordinate of the solution to the system of equations?

x- 5y =23\\-2x - 6y =2

Let

x- 5y =23--eq(1)\\-2x - 6y =2--eq(2)

Multiply equation 1 with 2 and add both equations

2x- 10y =46\\-2x - 6y =2\\-------\\-16y=48\\y=\frac{48}{-16}\\y=-3

So, we get the value of y = -3

Now, for finding x, put value of y in equation 1

x- 5y =23Put\:y=-3\\x-5(-3)=23\\x+15=23\\x=23-15\\x=8

So, we get x = 8

The solution set is (8,-3)

So, the x coordinate of the solution to the system of equations is 8

6 0
3 years ago
Find the factors of 42 prime or composite
Mariana [72]
7,1,and 42 if you think about it 
5 0
3 years ago
Read 2 more answers
7
LUCKY_DIMON [66]

The answer is B. 15 cm

5 0
3 years ago
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