Given, a parking lot charges $3 for first hour and $2 per hour after that.
So for t hours, the parking lot charges $3 for the first hour and after first hour there is 
hours left.
So for hours it will charge $2 per hour.
The charges for hours = $
.
Total charges for t hours for one car = $
Now for the second car, it will charge 75% of the first car.
So the charges for second car
=$[ 
]
=$
There are 3 cars. That parking charges for the third car is also 75% of the first car.
So for third car the parking charges are same as for the second car.
Total parking charges for 3 cars
= $
= $
We have got the required answer here.
The correct option is option C.
It would be “going up a steady rate through the origin”
The correct answer choice is D.
Compatible numbers to find two estimates 73÷4,858
70÷4,850 = 0.014
You sure it's not 4,858÷73
4,850÷70 =
______ _____ 69 2/7
70)4850. 7)485
42
65
63
The solution is the point of intersection between the two equations.
Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.
In the graph the first equation is in blue and the second in red.
The point of intersection = the solution = (-6 , -1)
If you dont have access to a graphing calculator you could draw the graphs by hand;
1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)
y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)
x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3
y = x + 5
x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7
2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph
3) Using a ruler draw a line connection all the dots of one graph and do the same for the other
4) The point of intersection is the solution
