The sides of a rectangle have the ratio 7:2. its perimeter is 207cm. Find the area

1 answer:

8 0

X - unit of length
w,l - the sides of a rectangle

7 : 2 ⇒ 7x : 2x

Perimeter: P = 207cm
Perimeter: P = 2w + 2l

therefore: 2w + 2l = 207 |divide both sides by 2

w + l = 103.5 (cm)

w : l = 7 : 2 ⇒ w : l = 7x : 2x ⇒ w = 7x; l = 2x

subtitute

7x + 2x = 103.5
9x = 103.5 |divide both sides by 9
x = 11.5 (cm)

7x = 7 · 11.5cm = 80.5cm
2x = 2 · 11.5cm = 23cm

w = 80.5cm; l = 23cm

Area = wl

Area: A = 80.5cm · 23cm = 1851.5cm²

You might be interested in

Find the equation of the line with slope = -8 and passing through (9,-73). Write your equation in the form

Morgarella [4.7K]

Answer:

1. Find the equation for the line that passes through (âˆ’2,9) that has slope 7/3 Give your answer in point-slope form. You do not need to simplify. 2. Find the equation of the line with slope = -4 and passing through (-6,29). Write your equation in the form y= 3. Find the equation for the line that passes through the points (7,âˆ’4) and (4,9). Give your answer in point-slope form. You do not need to simplify.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Thanks to whoever helped me out last time but I have another question.

yulyashka [42]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Simplify the expression.

spayn [35]

Answer:

C. $\huge\frac{1}{3x {y}^{2} {z}^{4}}$

Step-by-step explanation:

$(9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = ( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = \frac{1}{( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ \frac{1}{2} }} \\ \\ = \frac{1}{(3x {y}^{2} {z}^{4})^{2 \times \frac{1}{2} } } \\ \\ = \frac{1}{3x {y}^{2} {z}^{4}} \\ \\ \red{ \bold{ \therefore \: (9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } = \frac{1}{3x {y}^{2} {z}^{4}} }}\\$