Answer:
20
Step-by-step explanation:
H+S=50
2H+4S=140
4H+4S=200
4H+4S=200-
2H+ 4S =140
2H=60
H=30
50-30=20
Step-by-step explanation:
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Answer:
157
Step-by-step explanation:
Answer:
66 cm²
Step-by-step explanation:
From the given figure, and the question statement we have;
BD = 11 cm, AE = 7 cm, CF = 5 cm
The given quadrilateral ABCD consists of two triangles; ΔABD and ΔBCD
The area of quadrilateral ABCD = The sum of the areas of ΔABD and ΔBCD
The base length of the two triangles equals segment BD = 11 cm
The height of triangle ΔABD = 7 cm
The area of a triangle = (1/2) × Base length × Height
∴ The area of triangle ΔABD = (1/2) × 11 cm × 7 cm = 38.5 cm²
Similarly;
The area of triangle ΔBCD = (1/2) × 11 cm × 5 cm = 27.5 cm²
∴ The area of quadrilateral ABCD = 38.5 cm² + 27.5 cm² = 66 cm²
The area of the given figure (quadrilateral ABCD) = 66 cm².
Answer:
Step-by-step explanation:
