Answer:
An equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....
Step-by-step explanation:
The given expression is:
x2-16x+12
Break the constant term:
x^2-16x-36 +48=0
[x^2-16x-36] +48=0
Now break the middle term inside the brackets
(x^2-18x+2x-36)+48=0
Take the common
[x(x-18) +2(x-18)]+48=0
(x-18)(x+2)+48=0
Thus an equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....
The answer for this question would be <span>x + 7y > 3. You can figure this out because it is GREATER THAN. If it was greater than or equal to then the line would be solid (same with less than or equal to).</span>
Answer: 3.75z+12
For an equivalent expression, lets simplify the equation.
3/4(5z+16)
multiply both '5z' and '16' by 3/4
3.75z+12
To answer this question, start by identifying the total amount of income after 5 years for the first contract.
Since you start with 15,000 and get 1000 more each year, write an expression that represents this relationship.
15000 + 1000(5)
Multiply the parenthesis to begin to simplify your expression.
This leaves you with:
15000 + 5000
Add to find the total salary after five years with the first contract.
This ends up with:
$20,000
For the second contract, you have a diffferent rate of increase. Start by finding what one percent of the initial salary is. To do this, divide 14000 by 100.
14000/100 = 140
Then to find ten percent, multiply that number by 10.
140 x 10 =1400
So, each year you add 1400 dollars to the salary.
Now, using this information, set up an expression to model the salary for contract 2 after 5 years.
This should leave you with:
14000 + 1400(5)
Begin to simplify by multiplying what’s in the parenthesis.
1400 x 5 = 7000
Now rewrite your expression:
14000 + 7000
Add to find the total salary after 5 years with contract 2.
14000 + 7000 = 21000
So the salary with contract 2 is $21,000.
So, since $21000 is $1000 more than just $20000, contract 2 is the better option. I hope this helps! :)
