All categories

3 years ago

FOR FUN:- which years u have to be born in to get age of n in the n^2 year xD

Mathematics

1 answer:

Crazy boy [7]3 years ago

7 0

I think '2' is the only one that works.

You might be interested in

The Great Pyramid of Giza has an approximate height of 252 yards, and the square base has side lengths of approximately 152 yard

cestrela7 [59]

Answer:

b/38,304

Step-by-step explanation:

when you multiple 252 times 157 you will get 38,304.

3 0

3 years ago

What 2.484848... as a mixed number in simplest form

sergiy2304 [10]

Answer: 2 30303/62500

Hope this helps! :)

Step-by-step explanation:

7 0

3 years ago

Please help me it’s in my math class

JulijaS [17]

Answer:

1-70: Purple- 9/10= 0.18= 2 marbles

Orange- 16/50= 0.32= 3 marbles

Yellow- 6/50= 0.12= 1 marble

Green- 19/50= 0.38= 4 marbles

1-71: Part A. 3/6= 1/2

Part B. 4/6= 2/3

7 0

4 years ago

The price that Abigail paid for her snowboard, $84, is less than what Dan paid by $18. How much did Dan pay for his snowboard?

ratelena [41]

9514 1404 393

Answer:

$102

Step-by-step explanation:

Dan paid $18 more than $84:

18 + 84 = 102

Dan paid $102 for his snowboard.

5 0

3 years ago

Which container has the greatest surface area? (Use 3.14 for π .)

KatRina [158]

Answer:

The rectangular prism has the greatest surface area

Step-by-step explanation:

Verify the surface area of each container

case A) A cone

The surface area of a cone is equal to

$SA=\pi r^{2} +\pi rl$

we have

$r=6/2=3\ in$ ----> the radius is half the diameter

$l=10\ in$

substitute the values

$SA=(3.14)(3)^{2} +(3.14)(3)(10)=122.46\ in^{2}$

case B) A cylinder

The surface area of a cylinder is equal to

$SA=2\pi r^{2} +2\pi rh$

we have

$r=6/2=3\ in$ ----> the radius is half the diameter

$h=10\ in$

substitute the values

$SA=2(3.14)(3)^{2} +2(3.14)(3)(10)=244.92\ in^{2}$

case C) A square pyramid

The surface area of a square pyramid is equal to

$SA=b^{2} +4[\frac{1}{2}bh]$

we have

$b=6\ in$ ----> the length side of the square

$h=10\ in$ ----> the height of the triangular face

substitute the values

$SA=6^{2} +4[\frac{1}{2}(6)(10)]=156\ in^{2}$

case D) A rectangular prism

The surface area of a rectangular prism is equal to

$SA=2b^{2} +4[bh]$

we have

$b=6\ in$ ----> the length side of the square base

$h=10\ in$ ----> the height of the rectangular face

substitute the values

$SA=2(6)^{2} +4[(6)(10)]=312\ in^{2}$

6 0

3 years ago