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Lubov Fominskaja [6]
3 years ago
14

FOR FUN:- which years u have to be born in to get age of n in the n^2 year xD

Mathematics
1 answer:
Crazy boy [7]3 years ago
7 0
I think '2' is the only one that works.
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Cody stamped 460 envelopes in 30 minutes. How many envelopes per minute did Cody stamp?​
Leokris [45]

Answer:

15 1/3 envelopes in 1 minutes

Step-by-step explanation:

Take the number of envelopes and divide by the number of minutes

460 envelopes / 30 minutes

15.333333.... envelopes per minute

15 1/3 envelopes in 1 minutes

3 0
3 years ago
WILL GIVE BRAINLIEST
levacccp [35]

Answer:

a.  5^{2} x^{3}

b. 8^{3}

c. 4^{3} x^{4}

Step-by-step explanation:

a.  5^{2} x^{3}

b. 8^{3}

c. 4^{3} x^{4}

5 0
2 years ago
40 cats 20 dogs what is the ratio from cats to dogs
Stella [2.4K]
Ratio of cat : to dog = 40 : 20 = 2:1
8 0
3 years ago
Please help me
SVETLANKA909090 [29]

Answer:

B-$100=$372

The is is the smartest way I could look at this

OR

$372 - $100= b

Hope this helps

MARNIE OUT!

5 0
3 years ago
Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
3 years ago
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