Given:
Angled formed by ray BA and ray BC is 90 degrees.
To find:
The equation of line that bisects the angle formed by ray BA and ray BC.
Solution:
If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.
It is possible if the line passes though point B(-1,3) and other point (-2,4).
Equation of line is
Add 3 on both sides.
Therefore, the required equation of line is .
Answer:
6 and 7
Step-by-step explanation:
10(13-X) + X= 13-9X. 3×2=6. 7-6=1. 7+6=13
Answer:
y = root under 24 (evaluate it if necessary)
or y = 2 root 6
Step-by-step explanation:
Let the reference angle be x
for the triangle in left,
b = 6-4 = 2
Now,
taking x as refrence angle,
cosx = b/h
or, cosx = 2/h
again,
for the bigger triangle,
taking x as reference angle,
cosx = b/h
or, cosx = b/6
As we can see base of bigger triangle is equal to hypotenuse of triangle at the left,
Let's suppose its a
so, cosx = a/6 = 2/a
now,
a/6 = 2/a
or, a² = 12
now,
for bigger triangle, using pythagoras theorem,
h² = p²+b²
or, 6² = y² + a²
or, 36 = y² + 12
or, y² = 24
so, y = root under 24
