How to do this? ICT Excel there's a screenshot attached

Which option should you select to ignore all tracked changes in a document? To ignore all tracked changes in a document, you sho

Cloud [144]

Answer:

where is the options

Explanation:

4 0

3 years ago

This assignment is to code a simple hangman game. The game should choose a random word out of a list of words that are coded int

pshichka [43]

Answer:

Programming language not stated.

I'll use python for this question

Explanation:

import random

# library that we use in order to choose

# on random words from a list of words

words = ['rain, 'computer', 'science', 'program, 'python', 'mathematics', 'player', 'condition','reverse', 'water', 'board', 'geeks','learn','school','days','scholar','collar','flood','house','flies']

# Function will choose one random word from this list of words

word = random.choice(words)

print("Guess the word")

guesses = ''"

# 5 turns

turns = 5

while turns > 0:

# counts the number of times a user fails

failed = 0

# all characters from the input word taking one at a time.

for char in word:

# comparing that character with the character in guesses

if char in guesses:

print(char)

else:

print("_")

# for every failure 1 will be incremented in failure

failed += 1

if failed == 0:

# user will win the game if failure is 0 and 'You Win' will be given as output

print("You Win")

# this print the correct word

print("The word is: ", word)

break

# if user has input the wrong alphabet then it will ask user to enter another alphabet

guess = input("guess a character:")

# every input character will be stored in guesses

guesses += guess

# check input with the character in word

if guess not in word:

turns -= 1

# if the character doesn’t match the word then “Wrong” will be given as output

print("Wrong")

# this will print the number of turns left for the user

print("You have", + turns, 'more guesses')

if turns == 0:

print("You Loose")

7 0

3 years ago

What is a quasi vpn?

Natasha2012 [34]

Answer:

i don't think there is such thing as a quasi vpn

Explanation:

6 0

3 years ago

Which of the following galaxy types is most likely to be clearly identifiable, regardless of orientation? SBc

Reil [10]

Answer:

The most likely galaxy type to be identifiable regardless of orientation is: Irr

Explanation:

The Irr galaxies don't have a discernable or usual shape; that is why it is relatively easy to identify.

When we talk about E type galaxies, this statement proves itself by the way the cumulus of stars compounds the galaxy. The elliptical galaxies have the form of ellipses, with a reasonable distribution of stars. The degree of eccentricity is the number that complements the E letter; that's why E0 galaxies are almost spherical, while E7 is considerably elongated.

SBc, SBa galaxies are spiral; this means it can be flat in some angles difficulting their identification process; in this case, the last letter means the way the arms display their form, with "c" having a vague form and "a" well-defined arms. That's why in some angles can be mistreated as another type of galaxy.

3 0

3 years ago

Assume inputFile is a Scanner object used to read data from a text file that contains a number of lines. Each line contains an a

anzhelika [568]

Answer:

words.hasNext()

Explanation:

Given the code snippet below:

while (inputFile.hasNextLine()) {
String word = "";
String line = inputFile.nextLine();
Scanner words = new Scanner(line);
while (words.hasNext()) {
word = words.next();
}
System.out.println(word); }
}

We have a inputFile Scanner object that can read data from a text file and we presume the inputFile has read several rows of data from the text file. So long as there is another line of input data available, the outer while loop will keep running. In each outer loop, one line of data will be read and assign to line variable (Line 3). Next, there is another Scanner object, words, which will take the current line of data as input. To get the last word of that line, we can use hasNext() method. This method will always return true if there is another tokens in its input. So the inner while loop will keep running so long as there is a token in current line of data and assign the current token to word variable. The word will hold the last token of current line of data upon exit from the inner loop. Then we can print the output (Line 8) which is the last word of the current line of data.

7 0

3 years ago