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Hitman42 [59]
3 years ago
5

PLEASE HELP ME WILL MARK BRAINLIEST! Town planners are planning a 500 foot by 700 foot parking lot by making a scale drawing tha

t is 90 inches by 126 inches. What is the scale of inches in the drawing to inches in the actual object?
Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Answer:

The approximate value of the scale is 1:67

or the actual value without approximation is 1: 66 2/3 ( 66 while number , two over three)

Step-by-step explanation:

Here, we want to figure out the scale in inches of the drawing to the actual object.

The actual object is 500 ft by 700 ft

while the drawing is 90 inches by 126 inches

Mathematically, we know that 12 inches = 1 foot

So the actual object will be;

500(12) by 700(12)

= 6000 inches by 8400 inches

Now let’s make a division to get the scale;

6000/90 by 8400/126

we get 66.67 as answers on both ends

This is approximately equal to 67

So the scale we have here is 1:67

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Finds the slope of the line
Zinaida [17]

Answer:

4

Step-by-step explanation:

Slope=rise over run.

From bottom marked point (-3, -3) to the other (-2, 1)...

Rise= 4

Run= 1

4/1=4

Therefore, the slope is 4.

Hope this helps!! Have an amazing day ❤

6 0
3 years ago
Solve 11x+10y=32..... Will mark the brainliest!
erica [24]

The equation 11x + 10y = 32 is a linear equation, and the solution to the linear equation 11x + 10y = 32 is y = \frac{32 - 11x}{10}

<h3>How to solve the equation?</h3>

The equation is given as:

11x + 10y = 32

Subtract 11x from both sides

10y = 32 - 11x

Divide both sides by 10

y = \frac{32 - 11x}{10}

Hence, the solution to the linear equation 11x + 10y = 32 is y = \frac{32 - 11x}{10}

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

4 0
2 years ago
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
Student scored in the 83rd
melamori03 [73]

Answer:b

Step-by-step explanation:

5 0
3 years ago
Choose the correct simplification of the expression ( 4x/y)^2.
erik [133]

\large\displaystyle\text{$\begin{gathered}\sf \left(\frac{4x}{y}\right)^{2}   \end{gathered}$}

To raise 4x/y to a power, raise the numerator and denominator to the power, and then divide.

\large\displaystyle\text{$\begin{gathered}\sf \frac{(4x)^{2} }{y^{2} }  \end{gathered}$}

Expand (4x)².

\large\displaystyle\text{$\begin{gathered}\sf \frac{4^{2} x^{2} }{y^{2} }  \end{gathered}$}

Calculates 4 to the power of 2 and gets 16.

\boxed{\large\displaystyle\text{$\begin{gathered}\sf \frac{16x^{2} }{y^{2} }  \end{gathered}$} }

6 0
2 years ago
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