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qaws [65]
3 years ago
5

Which two ratios form a proportion? A) 4 20 and 1 5 B) 4 20 and 2 5 C) 20 4 and 1 5 D) 20 4 and 2 5

Mathematics
2 answers:
spayn [35]3 years ago
6 0

We have 4 / 20 = 1 / 5;

The correct answer is A);

DaniilM [7]3 years ago
5 0

You: bruh what is the answer

Me: .... Its A

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What is the answer to the following equation?<br>-x • 3x=?
Darina [25.2K]
The answer is -3 because:
A negative times a postive stays negative and also:
the variable "x" has an invisible one in front of it, so,
-1 x 3 = -3

Hope this helps :)
8 0
4 years ago
Need help with all questions
Vesnalui [34]

Answer:

14, 15

Step-by-step explanation:

5 0
3 years ago
The Campbell family has a disposable income of $60,000 annually. Assume that their marginal propensity to consume is 0.8 (the Ca
posledela
<span>Given the Keynesian equation C=A+MD, we find 10000 + (0.8 x 60000) = $58000. M is the Marginal propensity to consume, the A is the Autonomous consumption, and D is disposable income, giving Annual consumer spending as C.</span>
7 0
3 years ago
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
Please help, need for math hw and cant figure it out
swat32

The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

<h3>How to represent the quadratic function in standard form?</h3>

The quadratic function is given as

f(x) = -3x^2 + 6x - 2

The standard form of a quadratic function is represented as:

f(x) = ax^2 + bx + c

When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form

Where

a = -3

b = 6

c = -2

Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

Read more about quadratic function at

brainly.com/question/25841119

#SPJ1

7 0
1 year ago
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