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3 years ago

How do i tell if y=x^3+x^2 is even or odd?

Mathematics

1 answer:

Effectus [21]3 years ago

8 0

If a function is even, then f(-x) = x.

If a function is odd, then f(-x) = -x.

y = x³ + x² → f(x) = x³ + x² → -f(x) = -(x³ + x²) = -x³ - x²

f(-x) = (-x)³ + (-x)² = [(-1)(x)]³ + [(-1)(x)]² = (-1)³x³ + (-1)²x²

= -1x³ + 1x² =-x³ + x²

f(-x) ≠ f(x) and f(-x) ≠ -f(x)

y = x³ + x² is not odd and not even

Answer: neither

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2 years ago

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2 years ago

Y=-2x²-8x-5 domain and range

Jobisdone [24]

Answer:

Domain: All real numbers

Range: y≤3

Step-by-step explanation:

The given function is

$y = - 2 {x}^{2} - 8x - 5$

This is a polynomial function.

The domain is set of all values of x, that makes this function defined.

Since polynomial functions are defined everywhere, the domain is all real numbers.

To find the range we put the function in vertex form:

$y = - 2( {x}^{2} + 4x) - 5$

$y = - 2( {x}^{2} + 4x + 4) - 5 + - 4 \times - 2$

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The maximum value is 3

The function turns downward, hence the range is:

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2 years ago

X=5y: 2x+5y=60 A) 10,4 B) 15,4 C) 20,4 D) 25,4

elena-14-01-66 [18.8K]

Answer:

C) 20, 4

Step-by-step explanation:

X = 5y

2x + 5y = 60

substitute in 5y for x: 2(5y) + 5y = 60

10y + 5y = 60

15y = 60

y = 4

x = 5y

x = 5(4) = 20

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2 years ago

Read 2 more answers

The diameter of the base of the cone measures 8 units.

kati45 [8]

Answer: $32\pi$ cubic units.

Step-by-step explanation:

You can use this formula for calculate the volume of a cone:

$V_{cone}=\frac{1}{3}\pi r^2h$

Where "r" is the radius and "h" is the height.

You know that the diameter of the base of the cone measures 8 units, then, the radius can be found by dividing the diameter by 2:

$r=\frac{8units}{2}\\\\r=4units$

Since you already know that height and the radius, you can substitute them into the formula. Then, the volume of this cone is:

$V_{cone}=\frac{1}{3}\pi (4units)^2(6units)$

$V_{cone}=32\pi \ units^3$

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2 years ago