Answer:
Step-by-step explanation:
variable is the first one
evaluate is the second one
algebraic expression is the third one
substitute is the fourth one
Answer: yes
Step-by-step explanation:
There is not answer to your equation so technically anything could be X
Answer:2(p+q)
Step-by-step explanation:
P=(3a-q)
Remove bracket
P=3a-q
Add q to both sides of the equation
P+q=3a-q+q
P+q=3a
Divide both sides by 3
(p+q)/3=3a/3
(p+q)/3=a
a=(p+q)/3
6a=6 x a
6 x a=6 x (p+q)/3
6a=2(p+q)
Your answer will be
19+21+23
<h2>Greetings!</h2><h3>To solve this, you can multiply one of the equations by a number so that one of the unknown values are the same as the other equation. Or simply multiply both numbers before the x together:</h3>
(-2x + 5y = -15 ) x 5 =
-10x + 25y = -75
(5x+2y=-6) x -2 =
-10x -4y = 12
<h3>Now, you can add or minus the two equations, but seeing as both values before the x are negative we can add the two equations to cancel out the x:</h3>
-10x -4y = 12 +
-10x + 25y = -75 =
0x + 21y = -63
21y = -63
<h3>Simply divide -63 by 21 to find y:</h3>
-63 ÷ 21 = -3 , so the value of y = -3
<h3>Now you can substitute this value into one of the equations:</h3>
5x + 2y = -6
5x + 2(-3) = -6
5x = -6 - (-6)
5x = -6 + 6
5x = 0
x = 0
<h3>So that means x = 0 and y = -3</h3>
<h2>Hope this helps!</h2>