The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
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Answer:
I put it in the calc and it got
x=5i,−5i
3. you cannot simplify √30
The area of a triangle is A=1/2b*h
You have the base (b) and you have the area (A)
So, if you plug in what you know, you get this:
45.5=1/2*10*h
Simplify it:
45.5=5h
Now solve for h
Divide by 5 to get h alone:
9.1=h
Your height is 9.1cm
Hope this helps :)
