Answer:
6.9
Step-by-step explanation:
An octagon has 8 sides so:
55.2=8*x
x=55.2/8=6.9
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Step-by-step explanation:
Area for a right angle triangle = 1/2 bh
b = Base
h = Height
A = 1/2×bh
= 1/2 × 2c^3d^2 × 4c
= (2c^3d^2 × 4c) / 2
= c^3d^2 × 2c
= 2c^4 × d^2
Answer:
6^3= 216
4^4=256
216*256=55296
Step-by-step explanation:
no1 should sue u boo lm.fao
The six trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant. This is a first quadrant angle. sine of -17 pi over 3 is equal to square root of 3 over 2, cosine of -17 pi over 3 is equal to 1/2. tan -17 pi over 3 is equal to square root of 3. cosecant-17 pi over 3 is equal to 2/sqrt3, secant of -17 pi over 3 is 2 while cotangent -17 pi over 3 is equal to 1/sqrt 3
