1. What is the greatest common factor of 20x^6y+40x^4y^2−10x^5y^5 ?
2 answers:
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Area = length x width
x² + 12x = l * x
A.
First, you factor x from x² + 12x
area = x (x+12)
area = (x+12) * x
Length = x + 12
B.
If x = 10,
l = x + 12 = 10 +12 = 22
length = 22
and
Area = x² + 12x = 10² + 12(10) = 100 + 120 = 220
area = 220
Hope this helps :)
x² + 12x = l * x
A.
First, you factor x from x² + 12x
area = x (x+12)
area = (x+12) * x
Length = x + 12
B.
If x = 10,
l = x + 12 = 10 +12 = 22
length = 22
and
Area = x² + 12x = 10² + 12(10) = 100 + 120 = 220
area = 220
Hope this helps :)
Hope this helps with the answer to your question:) (sorry I didn't know how to do question 30)
