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Nitella [24]
3 years ago
15

1. What is the greatest common factor of 20x^6y+40x^4y^2−10x^5y^5 ?

Mathematics
2 answers:
Korvikt [17]3 years ago
7 0
The correct answer is D hope this helps you:)
ahrayia [7]3 years ago
4 0
Here, your expression is: <span>20x^6y+40x^4y^2−10x^5y^5
</span>Now, your coefficients are: 20, 40, 10
So, GCF of 20, 40 & 10 is 10

& Greatest common variable of x^6y, x^4y & x^5y^5 is x^4y
So, Your GCF for whole expression is 10x^4y

In short, Your Answer would be Option B

Hope this helps!
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A paper company needs to ship paper to a large printing business. The a paper will be
eimsori [14]

Given :

A paper company needs to ship paper to a large printing business.

The paper will be shipped in small boxes and large boxes.

Each small box of paper weighs 50 pounds and each large box of paper weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Find :

Determine the number of small boxes shipped and the number of large boxes shipped.

Calculations :

Let "S" be small boxes and "L" be large boxes.

Small box + Large box = 19

50S + 80L = 1280

→ 5S + 8L = 128

→ 5 (19 - L) + 8L = 128

→ 3L = 128 - 95

→ L = 33/3

→ L = 11ㅤㅤ

Finding the small box:

→ S = 19 - L

→ S = 19 - 11

→ S = 8

Therefore ,

Large boxes = 11.

Small boxes = 8.

orrrrrr

The number of small boxes is 8 and that of the large boxes is 11.

Step-by-step explanation:

Each small box of paper weighs 50 pounds and each large box of paper

weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Let there are x small boxes and y large boxes.

Then,

x + y = 19 ............ (1) and

50x + 80y = 1280

⇒ 5x + 8y = 128 ............... (2)

Now, solving equations (1) and (2) we get,

5( 19 - y) + 8y = 128

⇒ 3y = 128 - 95 = 33

⇒ y = 11

Now, from equation (1) we get, x = 19 - y = 19 - 11 = 8

Therefore, the number of small boxes is 8 and that of the large boxes is 11. (Answer)

8 0
2 years ago
What is the lateral area of a right cylinder if the radius of the base is 12 mm and the altitude of the cylinder is 5 times the
lakkis [162]
The lateral area of a cylinder is given by:
Area=πrl+2πr^2
radius,r=12 mm
length,l=5*12=60mm
therefore the lateral area will be:
Area=π*12*60
Area=2,261.95 mm^2
The area of the bases will be:
A=2*π*12^2=904.78 mm^s
The lateral area will be:
2,261.95+904.78
=3,166.73
=3167 mm^2
5 0
3 years ago
What is the arc length of arc CD in the circle below?
lord [1]
The length of the arc intercepted by a central angle is the ratio of the angle to 360 degrees times the circumference. From the given values above,
                            S = (30° / 360°) x 2 x π x (6 ft)
                                 S = π
The angle intercepted an arc which measures π feet. The answer is letter A. 
4 0
3 years ago
Read 2 more answers
HELP ME PLEASE!
Mashcka [7]

Answer:

Y=3x+12 (its the first option)

Step-by-step explanation:

I did the assignment.

8 0
3 years ago
Read 2 more answers
A store sells apples in 5-pound bags for $2.25. If the price per pound is the same, how much money would it cost for a 20-pound
dedylja [7]
I’m pretty sure the answer would be $9.00.
EXPLANATION:
2.25/5= 0.45
0.45x20= 9
ANSWER: $9.00
7 0
3 years ago
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