A fair coin is tossed three times.what is the probability that at least two heads will occur given that at most two heads have o ccurred?
1 answer:
<span>There are eight possible outcomes: HHH,HHT,HTH,HTT,THH,THT,TTH,TTT. Seven (all but HHH) have at most two heads. Three of these seven (HHT,HTH,THH) have at least two heads. The probability is therefore 3 in 7 or about 42.86%.</span>
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Step-by-step explanation:
27,345 × 113 - 27,345 × 13 ← factor out 27,345 from each term
= 27,345(113 - 13)
= 27,345 × 100
= 2,734,500
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