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adell [148]
2 years ago
5

Pls help quick

Mathematics
2 answers:
IRISSAK [1]2 years ago
8 0
Give the person above brainiest
Pepsi [2]2 years ago
4 0

hope it really helps......!!!!!

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How do you say 876543 in word form
Valentin [98]
Eight hundred seventy six thousand five hundred forty three.
7 0
3 years ago
Read 2 more answers
-2(x-3) &gt;-8<br> What is the answer
Vlad [161]

Answer:

x < 7

Step-by-step explanation:

First apply the -2 onto each term that it is being multiplied onto.

-2x + 6 > - 8

Now subtract six from both sides.

-2x > -14

Now divide by -2.

x < 7

<u>REMEMBER</u>

When doing greater than and less than equations like this, if you divide by a negative you must flip the greater than/less than.

5 0
3 years ago
The set of order pairs (-1, 8), (0,3) (1,2) and (2, -7) represent a function. What is the range of the function?
goldfiish [28.3K]
Answer: The range is the set {8, 3, 2, -7} which can be sorted to get {-7, 2, 3, 8}

------------------------------------------------------------------------------

Explanation:

The range is simply the set of possible y values. All you have to do is list all the y coordinates and surround the values in curly braces. The curly braces indicate a set. Every point is of the form (x,y). The y coordinate is the second value listed of each ordered pair.
8 0
3 years ago
Which expression shows the result of applying the distributive property to 3(1/5 x - 1/7)
steposvetlana [31]

Answer:

o.6x- 0.42857142857

Step-by-step explanation:

7 0
3 years ago
Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
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