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3 years ago

Estimate V17 to the nearest tenth.

Mathematics

1 answer:

spin [16.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

To round a number to the nearest tenth , look at the next place value to the right (the hundredths). If it's 4 or less, just remove all the digits to the right. If it's 5 or greater, add 1 to the digit in the tenths place, and then remove all the digits to the right.

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Coral beef grew 19.5 mm taller. how much did it grow in meters?

Serggg [28]

1 meter = 1,000 millimeter

We can solve this by making two proportion or millimeter over meter: $\frac{millimeter}{meter}$

$\frac{19.5 mm}{x meter} = \frac{1,000 mm}{1 m}$

Now you must solve for the unknown meter under the first proportion:

(1,000)(x meter) = 19.5 * 1

1,000(x meter) = 19.5

x meter = 0.0195 m

19.5 mm = 0.0195 m

Hope this helped! Let me know if you have any further questions

~ Just a girl in love with Shawn Mendes

6 0

3 years ago

A trapezoid has an area of 30 in2. If the lenghts of the bases are 4.8 and 5.2 in, what is the lenght?

harkovskaia [24]

Looking for the height, if trapezoid area equals (a+b)/2 x h then h = 2A/(a+b)
so h = 2(30)/(4.8+5.2) = 6

3 0

3 years ago

What would y=x^2 +x+ 2 be in vertex form

balu736 [363]

Answer:

$y = (x + \frac{1}{2} )^{2} + \frac{7}{4}$

Step-by-step explanation:

$y = {x}^{2} + x + 2$

We can covert the standard form into the vertex form by either using the formula, completing the square or with calculus.

$y = a(x - h)^{2} + k$

The following equation above is the vertex form of Quadratic Function.

Vertex — Formula

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

We substitute the value of these terms from the standard form.

$y = a {x}^{2} + bx + c$

$h = - \frac{1}{2(1)} \\ h = - \frac{ 1}{2}$

Our h is - 1/2

$k = \frac{4(1)(2) - ( {1})^{2} }{4(1)} \\ k = \frac{8 - 1}{4} \\ k = \frac{7}{4}$

Our k is 7/4.

Vertex — Calculus

We can use differential or derivative to find the vertex as well.

$f(x) = a {x}^{n}$

Therefore our derivative of f(x) —

$f'(x) = n \times a {x}^{n - 1}$

From the standard form of the given equation.

$y = {x}^{2} + x + 2$

Differentiate the following equation. We can use the dy/dx symbol instead of f'(x) or y'

$f'(x) = (2 \times 1 {x}^{2 - 1} ) + (1 \times {x}^{1 - 1} ) + 0$

Any constants that are differentiated will automatically become 0.

$f'(x) = 2 {x}+ 1$

Then we substitute f'(x) = 0

$0 =2x + 1 \\ 2x + 1 = 0 \\ 2x = - 1 \\x = - \frac{1}{2}$

Because x = h. Therefore, h = - 1/2

Then substitute x = -1/2 in the function (not differentiated function)

$y = {x}^{2} + x + 2$

$y = ( - \frac{1}{2} )^{2} + ( - \frac{1}{2} ) + 2 \\ y = \frac{1}{4} - \frac{1}{2} + 2 \\ y = \frac{1}{4} - \frac{2}{4} + \frac{8}{4} \\ y = \frac{7}{4}$