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kompoz [17]
3 years ago
11

(X+3) (x+4) Multiplying binomials

Mathematics
1 answer:
Georgia [21]3 years ago
3 0
(x+3)(x+4)
x^2+4x+3x+12
x^2+7x+12
You might be interested in
Please help me with this question.
padilas [110]
It would be: = 56 1/4 % = 225/4% = 225/4/100 = 225/400 = 9/16

In short, Your Answer would be 9/16

Hope this helps!
6 0
4 years ago
Which pair of fractions and mixed numbers have a common denominator of 20?
Tomtit [17]

Answer:

D 3 3/4 and 7/10

Step-by-step explanation:

A) 2 3/8 and 3/4  

4 goes into 20 evenly but 8 does not

NO

B) 1 5/6 and 2/5

5 goes into 20 evenly but 6 does not

NO  

C) 4 1/3 and 1/4

4 goes into 20 evenly but 3 does not

NO

D) 3 3/4 and 7/10

4 goes into 20 evenly and 10 goes into 20 evenly

YES 3 3/4 = 3 15/20 and 7/10 = 14/20

8 0
4 years ago
When solving negative one over five -1/5 (x − 25) = 7, what is the correct sequence of operations
aleksandr82 [10.1K]

The solution would be like this for this specific problem:

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) \cdot \left( {x - 25} \right) = 7 \cdot
\left( { - 5} \right)

 

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) = 1

 

The correct sequence of operations when solving negative one over five (x − 25) = 7 would be multiply each side by −5, and adding 25 to each side.

5 0
3 years ago
Mr. Marcus is splitting a huge new pack of colored pencils equally among his 25 students. After splitting the pencils he has 4 l
mamaluj [8]

Answer:

Each student got 17 pencils

Step-by-step explanation:

(429-5)/25=x

3 0
3 years ago
The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the orde
Akimi4 [234]

we are given

quadratic equation as

3x^2-4x+15=0

now, we can find b and c from

x^2+bx+c=0

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

3x^2-4x+15=0

\frac{3x^2-4x+15}{3}= \frac{0}{3}

\frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}

now, we can simplify it

x^2-\frac{4}{3}x+5= 0

now, we can compare it with

x^2+bx+c=0

we get

b=-\frac{4}{3}

c=5

so, we get order pair as

(b,c)=(-\frac{4}{3} , 5)..............Answer

6 0
3 years ago
Read 2 more answers
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