a. 9/10
explanation:
• the denominators (bottom number) are the same so there is no need to change to a common factor
• because the fractions have common factors, you add the top numbers (3+6) to get 9
• then you put the top number over the 10 (9/10) and it’s simplified as much as possible
b. 3/4
explanation:
• each denominator (bottom term) is a factor of 12 so you have to change each fraction to #/12
• to change 1/3, you multiply the top and bottom numbers by 4 (1x4 & 3x4 = 4/12)
• to change 1/4, you multiply the top and bottom numbers by 3 (1x3 & 4x3 = 3/12)
• to change 1/6, you multiple the top and bottom numbers by 2 (1x2 & 6x2 = 2/12)
• then you add each of the top numbers (4+3+2) and put it over the common denominator (12) to get 9/12
- both 9 & 12 are divisible by 3, so you simply by dividing both by 3 to get 3/4
c. 1/3
explanation:
•the denominators are the same, so you subtract 5-3 without changing the denominator & you get 2/6
• then, because both numbers are divisible by 2, you divide both by 2 and get 1/3
Since they are equal to 90 degrees. (complimentary angles)
6x-11+7x+10= 90
Combine like terms.
13x-1= 90
Add one to both sides.
13x= 91
x= 7
Plug that into the b.
7(7)+10
49+10
59
I hope this helps!
~kaikers
For the first part, it is y < 2x + 2
& the second part is (-1, -2)
Answer:
option a
Step-by-step explanation:
√16= 4 and 4 is a real as well as a rational number as well as integer amd whole numbers!
Hope it helps you....
Answer:
Choice C
Step-by-step explanation:
The quadrant in which an angle lies determines the signs of the trigonometric functions sin, cos and tan
If an angle Θ lies in quadrant IV, cos(Θ) is positive and both sin(Θ) and tan(Θ) are negative
Two of the trigonometric identities we can use are
1. and
2.
Using identity 1, we can solve for cos(s) and cos(t)
Since both angles lie in quadrant IV, both cos(s) and cos(t) must be positive so we only consider the positive signs of both values
Using identity 2, we can solve for cos(s-t)
Multiplying numerator and denominator of the first term by gives us the final expression as