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3 years ago

Which equation represents an inequality in the system of inequalities shown in the graph?

Mathematics

2 answers:

lozanna [386]3 years ago

8 0

For the first part, it is y < 2x + 2
& the second part is (-1, -2)

worty [1.4K]3 years ago

3 0

Answer:

For the first drop down option, It's the 3rd one and the Second one is the 2nd one

Step-by-step explanation:

I just did it on Edge!

You might be interested in

If 1 litre = 1000ml, then 2/10 a litre = ____.

kakasveta [241]

Answer:

→100ml.

Step-by-step explanation:

If 1 litre = 1000ml, then

$\small\sf{\quad\dfrac{2}{10} \: of \: 500 \: ml}$

$: \implies\small\sf{\dfrac{2}{10} \: of \: 500 \: ml}$

$: \implies\small\sf{\dfrac{2}{10} \times 500 \: ml}$

$: \implies\small\sf{\dfrac{2 \times 500 \: ml}{10}}$

$: \implies\small\sf{\dfrac{1000 \: ml}{10}}$

$: \implies\small\sf{\cancel{\dfrac{1000 \: ml}{10}}}$

$: \implies\small{\sf{100 \:ml}}$

<u>∴ The answer is 100 ml.</u>

6 0

3 years ago

Read 2 more answers

HELPPP WILL MARK THE RIGHT ANSWER BRAINLIEST

Mkey [24]

Answer:

B: 20.25

Step-by-step explanation:

32/24=27/x

Is this MAP testing?

3 0

3 years ago

Read 2 more answers

Trig proofs with Pythagorean Identities.

lorasvet [3.4K]

To prove:

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Solution:

$$LHS = \frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}$

Multiply first term by $\frac{1+cos x}{1+cos x}$ and second term by $\frac{1-cos x}{1-cos x}$ .

$$= \frac{1(1+\cos x)}{(1-\cos x)(1+\cos x)}-\frac{\cos x(1-\cos x)}{(1+\cos x)(1-\cos x)}$

Using the identity: $(a-b)(a+b)=(a^2-b^2)$

$$= \frac{1+\cos x}{(1^2-\cos^2 x)}-\frac{\cos x-\cos^2 x}{(1^2-\cos^2 x)}$

Denominators are same, you can subtract the fractions.

$$= \frac{1+\cos x-\cos x+\cos^2 x}{(1^2-\cos^2 x)}$

Using the identity: $1-\cos ^{2}(x)=\sin ^{2}(x)$

$$= \frac{1+\cos^2 x}{\sin^2x}$

Using the identity: $1=\cos ^{2}(x)+\sin ^{2}(x)$

$$=\frac{\cos ^{2}x+\cos ^{2}x+\sin ^{2}x}{\sin ^{2}x}$

$$=\frac{\sin ^{2}x+2 \cos ^{2}x}{\sin ^{2}x}$ ------------ (1)

$RHS=2 \cot ^{2} x+1$

Using the identity: $\cot (x)=\frac{\cos (x)}{\sin (x)}$

$$=1+2\left(\frac{\cos x}{\sin x}\right)^{2}$

$$=1+2\frac{\cos^{2} x}{\sin^{2} x}$

$$=\frac{\sin^2 x + 2\cos^{2} x}{\sin^2 x}$ ------------ (2)

Equation (1) = Equation (2)

LHS = RHS

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Hence proved.

5 0

4 years ago

PLEASE HELP ASAP. SOLVE FOR X AND Y. SHOW ALL WORK.

ss7ja [257]

The solution to the system of equations is (-3.88, 0.66) and (3.04, 1.09)

<h3>How to determine the solution to the system of equations?</h3>

The system of equations is given as:

x^2y + yx^2 = 20

1/x + 1/y = 5/4

Multiply through the equation 1/x + 1/y = 5/4 by 4xy

So, we have:

4x + 4y = 5xy

So, we have the following system of equations

4x + 4y = 5xy

x^2y + yx^2 = 20

Next, we plot the graph of the system of equations

4x + 4y = 5xy

x^2y + yx^2 = 20

See attachment for the graph of the system

From the attached system, we have the point of intersection to be

(x, y) = (-3.88, 0.66) and (3.04, 1.09)

Hence, the solution to the system of equations is (-3.88, 0.66) and (3.04, 1.09)

Read more about system of equations at

brainly.com/question/13729904

#SPJ1

6 0

2 years ago

Which is a correct first step for solving this equation -3x+2-5x-7=4x+2

Nataly_w [17]

Answer:

Your first step should be to separate the x's and the numbers.

This is how I would do it:

-3x+2-5x-7=4x+2

-3x-5x-4x=2-2+7

-12x=7

x=-7/12

4 0

3 years ago