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3 years ago

15

Pleaseeeeeeeeeeeeeee hellllllllllllp pleaseeeeee helpppppp

2 answers:

Lynna [10]3 years ago

8 0

-Use a protractor to measure the angles on question 10a
- use a ruler and a compass on the following question

For question 10b start by opening your compass to 2cm (use a ruler for this)
Draw it out
Double check it when you’re done - you should get 4cm as the diameter and 2cm for the radius

You don’t need to thank me, I hope this helped

anastassius [24]3 years ago

5 0

You can use a compass or a protector to answer

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P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).

Mila [183]

Answer:

The polynomial is:

$p(x) = -x^3 - 2x^2 + 5x + 6$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that $x_1 = -3, x_2 = -1, x_3 = 2$ . Thus

$p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)$

$p(x) = a(x - (-3))*(x - (-1))*(x-2)$

$p(x) = a(x+3)(x+1)(x-2)$

$p(x) = a(x^2+4x+3)(x-2)$

$p(x) = a(x^3+2x^2-5x-6)$

Passes through the point (1,12).

This means that when $x = 1, p(x) = 12$ . We use this to find a.

$12 = a(1 + 2 - 5 - 6)$

$-12a = 12$

$a = -\frac{12}{12}$

$a = -1$

Thus

$p(x) = -(x^3+2x^2-5x-6)$

$p(x) = -x^3 - 2x^2 + 5x + 6$

6 0

3 years ago

Can someone help me please id really appreciate it , i’ll give you brainliest

ozzi

Answer:

Alternate Exterior Angles Theorem

Step-by-step explanation:

By looking, we can see that they are exterior angles. Because 2 parallel lines are cut by a transversal, the angles are congruent.

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Step-by-step explanation:

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Which of the following is a like term for 2v^2?

DaniilM [7]

Answer:

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Step-by-step explanation:

Like terms are those whose variables are same.

Both 2v² and 4v² have v² in it.

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