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3 years ago

A recipe calls for 1/4 cups of flour but carter only has a measuring cup that holds 1/8.How can carter measur the flour he needs

Mathematics

1 answer:

Kipish [7]3 years ago

6 0

Answer:

Step-by-step explanation:

You want to find out how many 1/8 cups go into 1/4 cups so you 1/4 divided by 1/8.

When dividing fractions you flip the second fraction and change the operation from a division to a multiplication so.......

It will be 1/4 x 8/1

This will give you 8/4

8 divide by 4 is 2

So......

Carter has to fill the 1/8 cup twice to get how much he needs

Hope this helps!

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Describe Harriet Tubman’s childhood. What was one of her jobs as a child? How did she get a scar on her head?

Oksana_A [137]

Harriet Tubman's birthname was Araminta Ross. At a young age of 11, she was hired out as nursemaid for a small baby. She had to stay awake all night to make sure that the baby would not cry. She got the scar on her head when she refused to help in the punishment of another young slave.

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3 years ago

X increased by 61% i really need hep and show me how you got it :))))

Harrizon [31]

The answer would me x + 6.01
And increase means to add so x + 61% = x + 6.01

Hope this helps

Have a great day/night

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3 years ago

Juan and Alex are both saving money for college. Juan saves $150 per month and currently has $2000 in the bank. Alex saves $250

joja [24]

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3 years ago

The system of equations below has no solution.

mixer [17]

Answer:

Second option: 0 = 26

Explanation:

This is the given system of equations:

$\frac{2}{3} x+\frac{5}{2} y=15\\ \\ 4x+15y=12$

A linear combination of the system is any equation formed by the algebraic addition of both equations, one or both multiplied by an arbitrary constant.

To prove that the given system has no solution you could multiply the first equation times 6 (to get rid of the fractions), multiply the second equation times - 1, and add the two results:

1. First equation times 6:

$6\times\frac{2}{3} x+6\times\frac{5}{2}y=6\times 15\\ \\ 4x+15y=90$

2. Second equation times - 1:

$-4x-15y=-12$

3. Add the two new equations:

$0=78$

4. Conclusion:

Since 0 = 78 is false, no matter what the value of x and y are, the conclusion is that the system of equations has not solution.

The only choice that represents that same situation is the second one, 0 = 26. That is a possible linear combination that represents that the system of equations has no solutions.

In fact, you might calculate the exact factors by which you had to multiply each one of the original equations to get 0 = 26, but it is not necessary to tell that that option represents a possible linear combination for the given system of equations.

7 0

3 years ago

Read 2 more answers

A national survey conducted in 2011 among a simple random sample of 1,507 adults shows that 56% of Americans think the Civil War

Drupady [299]

Answer:

a) $z=4.658$

$p_v =P(z>4.65)=1-P(z$

b) Using the significance level assumed $\alpha=0.05$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion of Americans who thinks that the Civil War is still relevant to American politics and political life is higher than 50%.

c) The 90% confidence interval would be given (0.527;0.593).

We are confident that about 54% to 59% of all Americans think the Civil War is relevant.

Step-by-step explanation:

I )Part a

1) Data given and notation

n=1507 represent the random sample taken

X represent the Americans who thinks that the Civil War is still relevant to American politics and political life

$\hat p$ estimated proportion of Americans who thinks that the Civil War is still relevant to American politics and political life in the sample

$p_o=0.5$ is the value that we want to test since the problem says majority

$\alpha=0.05$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of Americans who thinks that the Civil War is still relevant to American politics and political life

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of Americans who thinks that the Civil War is still relevant to American politics and political life exceeds 50%(Majority). :

Null Hypothesis: $p \leq 0.5$

Alternative Hypothesis: $p >0.5$

We assume that the proportion follows a normal distribution.

This is a one tail upper test for the proportion of union membership.

The One-Sample Proportion Test is "used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ ".

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =1507*0.5=753.5>10$

$n(1-p_o)=1507*(1-0.5)=753.5>10$

3) Calculate the statistic

The statistic is calculated with the following formula:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}$

On this case the value of $p_o=0.5$ is the value that we are testing and n = 1507.

$z=\frac{0.56 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1507}}}=4.658$

The p value for the test would be:

$p_v =P(z>4.65)=1-P(z$

II) Part b

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

Based on the alternative hypothesis the p value would be given by:

$p_v =P(z>4.65)=1-P(z$

Using the significance level assumed $\alpha=0.05$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion of Americans who thinks that the Civil War is still relevant to American politics and political life is higher than 50%.

III) Part c

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.56 - 2.58 \sqrt{\frac{0.56(1-0.56)}{1507}}=0.527$

$0.56 + 2.58 \sqrt{\frac{0.56(1-0.56)}{1507}}=0.593$

And the 90% confidence interval would be given (0.527;0.593).

We are confident that about 54% to 59% of all Americans think the Civil War is relevant.

And this result agrees with the result of part b, since the interval not contains the value of 0.5 we can conclude that the proportion of Americans who thinks that the Civil War is still relevant to American politics and political life it's higher than 0.5 at 90% of confidence.

7 0

3 years ago