Over 200 mph generally now I says 300 mph
Answer: E. Never
geometric average return can NEVER exceed the arithmetic average return for a given set of returns
Explanation:
The arithmetic average return is always higher than the other average return measure called the geometric average return. The arithmetic return ignores the compounding effect and order of returns and it is misleading when the investment returns are volatile.
Arithmetic returns are the everyday calculation of the average. You take the series of returns (in this case, annual figures), add them up, and then divide the total by the number of returns in the series. Geometric returns (also called compound returns) involve slightly more complicated maths.
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
Answer:
The complete method is as follows:
public static int divBySum(int[] arr, int num){
int sum = 0;
for(int i:arr){
if(i%num == 0)
sum+=i;
}
return sum;
}
Explanation:
As instructed, the program assumes that arr has been declared and initialized. So, this solution only completes the divBySum method (the main method is not included)
This line defines the method
public static int divBySum(int[] arr, int num){
This line declares and initializes sum to 0
int sum = 0;
This uses for each to iterate through the array elements
for(int i:arr){
This checks if an array element is divisible by num (the second parameter)
if(i%num == 0)
If yes, sum is updated
sum+=i;
}
This returns the calculated sum
return sum;
}
