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Margaret [11]
3 years ago
9

What is 4 and 2/5 plus 5 and 3/10

Mathematics
2 answers:
zhuklara [117]3 years ago
7 0

Answer:

decimal form 9.7

mixed number 9 7/10

Step-by-step explanation:

zalisa [80]3 years ago
5 0

Answer:

9.7

Step-by-step explanation:

4+(2÷5)+5+(3÷10)=

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0.291×0.34=0.09894

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Answer:

Its B

Step-by-step explanation:

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You can spend at most $60 on beads. A bag containing red beads costs $2 per bag. A bag containing blue beads costs $3 per bag. Y
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For this case, the first thing we must do is define variables.
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 We now write the inequations system:
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x\ \textgreater \  y
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 a system of linear inequations that represents the situation is:
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8 0
3 years ago
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All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
A football field measures 120 yards long and 54 yards wide. We know that the team can fit 26 players in 5 yards by 8 yards box.
wariber [46]

Answer:

4,212 people

Step-by-step explanation:

We are given;

  • Dimensions of the football field are 120 yards by 54 yards
  • 26 players can fit in a box measuring 5 yards by 8 yards

We are required to determine the number of people that can fit in the football field.

  • We are going to get the area of the field first;

Area = length × Width

Area of the field = 120 yards × 54 yards

                          =  6480 square yards

  • Then we get the area of the box

Area of the box = 5 yards × 8 yards

                           = 40 square yards

  • We then determine the number of boxes that can fit in the football field

Number of boxes = Area of the foot ball field ÷ Area of one box

                             = 6480 sq yards ÷ 40 sq yards

                             = 162 boxes

But, 26 people can fit in one box

Therefore,

Total number of people that can fit in the field is given by multiplying the number of boxes that can fit in the field by the number of people in a box

That is, Number of people = 26 players × 162 boxes

                                            = 4,212 people

Therefore, the number of people that can fit in the football field is 4,212 people.

6 0
3 years ago
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