Answer:
Step-by-step explanation:
A ball is thrown up in the air: ex:) the diagram starts from the bottom point which represents a ball being thrown from a bottom level then falling down elsewhere
If you mean slope, then the slope of the line is 4/5
V=hpir^2
h=5
r=8
v=5pi8^2
v=5pi64
v=320pi cubic inches
Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
Step-by-step explanation:
f ( X) = ( 2X - I ) / 2X ^ 2 - 9X + 10
= 2X-1 ) /( 2X- 5 ) ( x - 2 )
set of zeros of denominator are :
2X- 5 . = 0
X= 5/2
or
X-2=0
X=2
set of zeros of denominator = { 5/2 ,2 }
domain = R - { 5/2,2 }