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KonstantinChe [14]
3 years ago
15

A fairly good estimate for a long-term loan with a moderate or high interest rate is that the monthly payment is _____ as large

as the principal times the monthly interest rate.
Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:

at least

Step-by-step explanation:

A fairly good estimate for a long-term loan with a moderate or high interest rate is that the monthly payment is<u><em> AT LEAST</em></u> as large as the principal times the monthly interest rate.

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Consider the function f(x) = 20/√x and its second-degree polynomial P2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. Compute the val
krok68 [10]

Answer:

f (0.8) = 22.3607 and P_{2} (0.8) = 22.300.

Step-by-step explanation:

According to the statement, f (x) = \frac{20}{\sqrt{x}}  and  P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2. Based on these definitions, at x=0.8 produce:

f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607.  On the other hand, you have to:

P_{2} (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2

P_{2} (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300

Then, it can be affirmed that f (0.8) = 22.3607 and P_{2} (0.8) = 22.300.

3 0
4 years ago
I WILL GIVE BRAINLIEST Identify the coefficients in the following expression.
padilas [110]

Step-by-step explanation:

the coefficients are the whole numbers accompanied by the variable. would be: 3, 5, 1, 13

8 0
3 years ago
Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

7 0
3 years ago
0.00003852 in standardform
umka21 [38]

Answer:

963/25000000

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can u help me with the problem below<br><br><br>(-4)- 6​
Keith_Richards [23]

Since you are subtracting a negative you would add them together equaling -10

7 0
4 years ago
Read 2 more answers
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