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2 years ago

Please help thanks very much

Mathematics

1 answer:

erik [133]2 years ago

4 0

X/(x+5) = (x-2)/(x+1)
x(x+1) = (x -2) (x + 5)
x^2 + x = x^2 - 2x + 5x - 10
x = 3x - 10
3x - x = 10
2x = 10
x = 5

answer is A
5

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Ill give you Brainlyest! I need help ASAP work shown, please!! problems 8-15

8_murik_8 [283]

Using the segment addition theorem, the solutions are:

5. x = 17

6. x = 7

7. x = 14

BC = 27

CD = 61

BD = 88

8. AB = 26

9. LJ = 46

10. x = 3

11. FG = 15

12. QS = 34

13. BC = 26

14. EG = 19

15. QS = 68

<h3>How to Apply the Segment Addition Theorem?</h3>

The segment addition theorem would be used to solve the problems as shown below:

5. UW = UV + VW [segment addition theorem]

Substitute

6x - 35 = 19 + 4x - 20

6x - 4x = 35 + 19 - 20

2x = 34

x = 17

6. HJ = HI + IJ [segment addition theorem]

Substitute

7x - 27 = 3x - 5 + x - 1

7x - 3x - x = 27 - 5 - 1

3x = 21

x = 7

7. BD = BC + CD [segment addition theorem]

Substitute

7x - 10 = 4x - 29 + 5x - 9

7x - 4x - 5x = 10 - 29 - 9

-2x = -28

x = 14

BC = 4x - 29 = 4(14) - 29 = 27

CD = 5x - 9 = 5(14) - 9 = 61

BD = 7x - 10 = 7(14) - 10 = 88

8. BC = BD

Substitute

2x + 1 = 5x - 26

2x - 5x = -1 - 26

-3x = -27

x = 9

AB = 43 - BC

AB = 43 - 2x + 1 = 43 - 2(9) + 1 = 26

9. 7x - 10 = 9x - 11 - (x + 3)

7x - 10 = 9x - 11 - x - 3

7x - 9x + x = 10 - 11 - 3

-x = -4

x = 4

LJ = 28 + 7x - 10 = 28 + 7(4) - 10

LJ = 46

10. 8x + 11 = 12x - 1

8x - 12x = -11 - 1

-4x = -12

x = 3

11. 11x - 7 = 3x + 9

11x - 3x = 7 + 9

8x = 16

x = 2

FG = 11x - 7 = 11(2) - 7

FG = 15

12. 5x - 3 = 21 - x

5x + x = 21 + 3

6x = 24

x = 4

QS = 2(5x - 3) = 10x - 6 = 10(4) - 6

QS = 34

13. 8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

8x - 6x = 20 - 2

2x = 18

x = 9

BC = AB = 3x - 1 = 3(9) - 1

BC = 26

14. 5x - 1 = 7x - 13

5x - 7x = 1 - 13

-2x = -12

x = 6

EG = 6x - 4 - 13 = 6(6) - 4 - 13

EG = 19

15. RT - ST = RS

Substitute

8x - 43 - (4x - 1) = 2x - 4

8x - 43 - 4x + 1 = 2x - 4

4x - 42 = 2x - 4

4x - 2x = 42 - 4

2x = 38

x = 19

QS = 2(RS)

QS = 2(2x - 4) = 4x - 8 = 4(19) - 8

QS = 68

Learn more about the segment addition theorem on:

brainly.com/question/28263183

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1 year ago

Emilio’s family volunteers at the local soup

Mice21 [21]

Answer:

Emilio will have both activities again on the same day after 90 days from this Saturday.

Step-by-step explanation:

To solve this question list the multiples of 30 and 9 to find the first common multiple because the two activities will happen again in a number divisible by both 30 and 9.

∵ The multiples of 30 are: 30, 60, 90, 120, ............

∵ The multiples of 9 are: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, .....

→ The common multiple is 90

∴ The common multiple of 30 and 9 is 90

→ That means the activities will meet again after 90 days from

this Saturday

Emilio will have both activities again on the same day after 90 days from this Saturday.

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2 years ago

A line contains the points (-5, 3) and (0, -7). What is the equation of this line in slope-intercept form?

pychu [463]

Answer:

D. y = –2x – 7

Step-by-step explanation:

First, find the rate of change [slope]:

-y₁ + y₂\-x₁ + x₂ = m

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In this case, the y-intercept of [0, -7] is ALREADY given to you, so we would not have to go further in this case.

I am joyous to assist you anytime.

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2 years ago

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Which is the correct first step in finding the area of the base of a cylinder with a volume of cubic meters and a height of 6.5

MAXImum [283]

The correct first step in finding the area of a base of a cylinder is to find the length of radius of the circular base.

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3 years ago

Alonzo wrote the equation x = 2+4y-5. Which equation is equivalent?

Rainbow [258]

Consider the equation $x = 2+4y-5$ , it can be expressed as $x = 4y-3$ .

Now, we have to write the equivalent equation.

Since, Equivalent equations are those equations which have exactly same solution. We can say that the two equations are equivalent if solution of one equation is the solution of other equation.

So, consider the equation $x = 4y -3$

Equivalent equation can be obtained by multiplying the given equation by any number say '2'.

Multiplying both sides of the given equation by '2'.

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2 years ago