The 12th term of the sequence is 133
<h3>How to determine the 12th term?</h3>
The nth term is given as:
Tn = 11n + 1
The 12th term is calculated as:
T(12) = 11(12) + 1
Evaluate
T(12) = 133
Hence, the 12th term of the sequence is 133
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Answer:
The absolute brightness of the Cepheid star after a period of 45 days is -5.95
Step-by-step explanation:
Since the absolute magnitude or brightness of a Cepheid star is related to its period or length of its pulse by
M = –2.78(log P) – 1.35 where M = absolute magnitude and P = period or length of pulse.
From our question, it is given that P = 45 days.
So, M = –2.78(log P) – 1.35
M = –2.78(log 45) – 1.35
M = –2.78(1.6532) – 1.35
M = -4.60 - 1.35
M = -5.95
So, the absolute magnitude or brightness M of a Cepheid star after a period P of 45 days is -5.95
Answer:
91
254
Step-by-step explanation:
Answer:
The smaller number: a = 10
The larger number is 32
Step-by-step explanation:
a - the smaller number
2a - twice the smaller number
2a+12 - twelve more than the twice smaller number (the larger number)
a + 2a+12 - the sum of the numbers
a + 2a+12 = 42
-12 -12
3a = 30
÷3 ÷3
a = 10
2a+12 = 2×10+12 = 20+12 = 32
Check: 10+32=42