Question

What is the 8th term of the geometric sequence 8,16,32

Answer 1

the 8th term of the geometric sequence 8, 16, 32 is 1024

Explanation

we know that

geometric sequence 8, 16, 32

the question is

the 8th term

the answer is

first we have to find the ratio

$\sf r= \frac{ U_2}{U_1} \\ \sf r= \frac{ 16}{8} \\ \sf r = 2$

than, we have to find the 8th term

$\sf U_n = ar^{n-1} \\ \sf U_8 = 8 \times 2^{8-1} \\ \sf U_8 = 8 \times 2^7 \\ \sf U_8 = 8 \times 128 \\ \bold {\sf U_8 = 1024}$

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About geometric pattern

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Answer details

grade: 7th

subject: mathematics

chapter: sequence

keywords: geometric sequence