What is the 8th term of the geometric sequence 8,16,32

Mathematics

1 answer:

ratelena [41]3 years ago

7 0

the 8th term of the geometric sequence 8, 16, 32 is 1024

<h2>Explanation</h2>

geometric sequence 8, 16, 32

<u>the </u><u>question</u><u> </u><u>is</u>

the 8th term

<u>the </u><u>answer </u><u>is</u>

first we have to find the ratio

$\sf r= \frac{ U_2}{U_1} \\ \sf r= \frac{ 16}{8} \\ \sf r = 2$

than, we have to find the 8th term

$\sf U_n = ar^{n-1} \\ \sf U_8 = 8 \times 2^{8-1} \\ \sf U_8 = 8 \times 2^7 \\ \sf U_8 = 8 \times 128 \\ \bold {\sf U_8 = 1024}$

<h2>Learn more</h2>

About geometric pattern

brainly.com/question/16762536

<h2>Answer details</h2>

grade: 7th

subject: mathematics

chapter: sequence

keywords: geometric sequence

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