Answer:
$0 < p ≤ $25
Step-by-step explanation:
We know that coach Rivas can spend up to $750 on 30 swimsuits.
This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:
C ≤ $750
Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:
C = 30*p
Then we have the inequality:
30*p ≤ $750.
To find the possible values of p, we just need to isolate p in one side of the inequality.
So we can divide both sides by 30 to get:
(30*p)/30 ≤ $750/30
p ≤ $25
And we also should add the restriction:
$0 < p ≤ $25
Because a swimsuit can not cost 0 dollars or less than that.
Then the inequality that represents the possible values of p is:
$0 < p ≤ $25
Answer:
No Solution
Step-by-step explanation:
6 - 3x = 4 - x - 3 - 2x (Given)
6 - 3x = -1 -3x (combine like terms)
7 (addition)
The x cancels each other out so no solution.
Answer:
The answer is 113
Step-by-step explanation:
6^2 + 7(3^2 + 8 - 6)
36 + 7(9 + 8 - 6)
36 + 7(11)
36 + 77
113
Answer:
C) f(x) = 6.25x + 3
Step-by-step explanation:
In order to know which one of the functions could produce the results in the table we simply need to substitute the number of candy bars for x in the function and solve it to see if it provides the correct total weight shown in the table. If we do this with the functions provided we can see that the only one that provides accurate results would be
f(x) = 6.25x + 3
We can input the # of candies for x and see that it provides the exact results every time as seen in the table.
f(x) = 6.25(1) + 3 = 9.25
f(x) = 6.25(2) + 3 = 15.50
f(x) = 6.25(3) + 3 = 21.75
f(x) = 6.25(4) + 3 = 28
