Sorry im a little late but here's how i did it.
Hope this helps! :)
Centroid, orthocenter, circumcenter, and incenter are the four locations that commonly concur.
<h3>Explain about the concurrency of medians?</h3>
A segment whose ends are the triangle's vertex and the middle of the other side is called a median of a triangle. A triangle's three medians are parallel to one another. The centroid, also known as the point of concurrency, is always located inside the triangle.
The incenter of a triangle is the location where the three angle bisectors meet. The only point that can be inscribed into the triangle is the center of the circle, which is thus equally distant from each of the triangle's three sides.
Draw the medians BE, CF, and their intersection at point G in the triangle ABC. Create a line from points A through G that crosses BC at point D. We must demonstrate that AD is a median and that medians are contemporaneous at G since AD bisects BC (the centroid)
To learn more about concurrency of medians refer to:
brainly.com/question/14364873
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Answer:
(13×14×6)/3= 364 centimeter cube
I answered wrongly cuz forgot to divide by 3
my mistake
Question 1
Because the period is 2π, and the amplitude is 1obtain
f(x) = sin(x)
Because the horizontal shift is π, obtain
f(x) = sin(x - π)
Because the vertical shift is -4, obtain
f(x) = sin(x - π) - 4
Answer: 1. f(x) = sin(x - π) - 4
Question 2
The radius is 36/2 = 18 in.
1 revolution (360°) is the circumference, which is
2π(18) = 36π in
When the revolution is 62°, the distance traveled is
(62/360)*(36π) = (31/5)π in
Answer: 3. (31π)/5
Question 3.
Consider f(x) = 3cos(2x-π) - 1
f(0) = 3cos(-π) - 1 = -4
f(π/2) = 3cos(0) - 1 = 2
Rate of change = (2+4)/(π/2) = 12/π
From the graph, the rate of change of g(x) is
3/(π/2) = 6/π
Consider h(x) = sin(x) - 4
h(0) = 0 - 4 = -4
h(π/2) = 1 - 4 = -3
Rate of change = (-3+4)/(π/2) = 2/π
Therefore h(x) has the smallest rate of change
Answer: h(x)
X=1/2 I’m mostly guessing but for math just use the app called photo math it’s helps with math equations but not math written problems
