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mrs_skeptik [129]
3 years ago
7

A pole that is 3.1m tall casts a shadow that is 1.46m long. At the same time, a nearby building casts a shadow that is 36.75m lo

ng. How tall is the building?
Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0
You have to find the angle of sunlight and the pole , which then cast a shadow
length of the pole is equal to 3.1m
creating a hypotenuse of 4.52m
the angle will be
[email protected] = opposite side / hypotenuse
= 1.46/4.52
= 0.32 that's 18.66 °
now for the building sin18.66° = opposite/hypotenuse
0.32 = 36.75/ hypotenuse
hypotenuse = 114.84 m
thus using Pythagoras theorem
114.84*114.84 = 36.75*36.75 + x^2
which comes around = 108.8 roughly 109 metres long
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B the plane has only one dimension
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If ten is no more than four times the sum of twice a number and three how do I write and work this for algebra
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(2x+3)*4 is less than or equal to 10. For x, the number, you would get x is greater than or equal to -1/4.
7 0
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Solve the following system of equations algebraically. Verify your solution either graphically or by using matrices.
LiRa [457]
3x - y = 0 . . . (1)
5x + 2y = 22 . . . (2)

From (1), y = 3x . . . (3)

Putting (3) into (2) gives:
5x + 2(3x) = 22
5x + 6x = 22
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5 0
3 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0
3 years ago
18 2by5-4 1by10 find the difference
luda_lava [24]

Given:

The expression is:

18\dfrac{2}{5}-4\dfrac{1}{10}

To find:

The difference.

Solution:

We have,

18\dfrac{2}{5}-4\dfrac{1}{10}

It can be rewritten as:

=\dfrac{90+2}{5}-\dfrac{40+1}{10}

=\dfrac{92}{5}-\dfrac{41}{10}

Taking LCM, we get

=\dfrac{184-41}{10}

=\dfrac{143}{10}

=\dfrac{140+3}{10}

=14\dfrac{3}{10}

Therefore, the value of the difference is 14\dfrac{3}{10}.

3 0
3 years ago
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