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Vikki [24]
3 years ago
9

If(2p+3)(p+5)=p2 +p+,whatisthevalueof++?

Mathematics
1 answer:
Zarrin [17]3 years ago
5 0

Answer:   (p - 1) • (5p + 3)

Step-by-step explanation: Changes made to your input should not affect the solution:

(1): "p2"   was replaced by   "p^2".  

STEP

1

:

Equation at the end of step 1

 (5p2 -  2p) -  3

STEP

2

:

Trying to factor by splitting the middle term

2.1     Factoring  5p2-2p-3  

The first term is,  5p2  its coefficient is  5 .

The middle term is,  -2p  its coefficient is  -2 .

The last term, "the constant", is  -3  

Step-1 : Multiply the coefficient of the first term by the constant   5 • -3 = -15  

Step-2 : Find two factors of  -15  whose sum equals the coefficient of the middle term, which is   -2 .

     -15    +    1    =    -14  

     -5    +    3    =    -2    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -5  and  3  

                    5p2 - 5p + 3p - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

                   5p • (p-1)

             Add up the last 2 terms, pulling out common factors :

                   3 • (p-1)

Step-5 : Add up the four terms of step 4 :

                   (5p+3)  •  (p-1)

            Which is the desired factorization

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Which other expression has the same value as (-14)-(-8)
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Answer:

(-14)+(-8)

Step-by-step explanation:

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How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

5 0
3 years ago
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Answer:

1. 74 because 8(10) - 6

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4. A

5.a

6. 20.5

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8.a

9.a

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Step-by-step explanation:

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