Step-by-step explanation:
log2x = 1 - log(x+4)
log2x = log10 - log(x+4)
log2x = log[10/(x+4)]
2x = 10/(x+4)
2x(x+4) = 10
2x² + 8x - 10 = 0
÷2 both sides of equation
x² + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5, 1
x isn't be -5 because logA, A need to be > 0
So, x value is 1
When you multiply a same number but with different powers, you can simply add the powers together. So, in your question, add the powers -1 and -7 together.
7^(-1) x 7^(-7) = 7^(-8)
When you divide a same number but with different powers, you subtract the power at the top with the power from the denominator. So, -8 - (-7) = -1.
7^(-8) / 7^(-7) = 7^(-1)
So your answer would be 7^(-1).
Hopefully my explanation was clear?
Answer:
x=2
y = 0
Step-by-step explanation:
3x + y = 6 -------------(i)
5x - 2y = 10 -------------(ii)
Multiply (i) by 2 ===> 6x +2y = 12
(ii) ===> <u> 5x - 2y = 10</u>
add ============> 11x = 22
x = 22/11
x = 2
Substitute x = 2 in (i)
3*2 + y = 6
6 + y = 6
y = 6 - 6
y = 0
Answer:the answer is
Step-by-step explanation:
First convert 7 1/2 to an improper fraction
15/2 ÷ 3/4
Division of fractions hold the first fraction replaces ÷ with x then flip the second fraction
15/2 x 4/3
Multiply the tops 15x4 =60
Over the bottoms multiplied together 2x3=6
60/6=10
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