Two numbers have a distance of 5 units from 0 on a number line. The numbers can be graphed on the number line as points A and B.
2 answers:
Drag A to negative 5 and B to positive 5.
Answer:
Point A is labeled at x=-5 and point B is labeled at x=5.
Step-by-step explanation:
It is given that two numbers have a distance of 5 units from 0 on a number line.
Let the unknown number be x.
Case 1: x is 5 units less than 0.
The point A is labeled at x=-5.
Case 2: x is 5 units more than 0.
The point B is labeled at x=5.
You might be interested in
Answer:
D
Step-by-step explanation:
its the closest to the answer i got so that must be it
Answer:
Your answer is y.
Step-by-step explanation:
4y+2y-5y given
=6y-5y add
=y subtract
Option C
<em><u>Solution: </u></em>
We have to solve for "x"
From given,
Solve for brackets
Use distributive property
a(b + c) = ab + ac
Therefore,
Combine the constants
Move the variables to left side of equation
Combine the like terms
Thus option C is correct
The Answer is C 5/6
250/300 reduced and simplified is 5/6
If the given pairs are supposed to represent points on the graph, you apparently have a graph in which y is inversely related to x. The constant of variation is the product of x and y values: 24 . (matches selection B.)