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3 years ago

Two numbers have a distance of 5 units from 0 on a number line. The numbers can be graphed on the number line as points A and B.

Mathematics

2 answers:

Verizon [17]3 years ago

7 0

Drag A to negative 5 and B to positive 5.

ser-zykov [4K]3 years ago

6 0

Answer:

Point A is labeled at x=-5 and point B is labeled at x=5.

Step-by-step explanation:

It is given that two numbers have a distance of 5 units from 0 on a number line.

Let the unknown number be x.

Case 1: x is 5 units less than 0.

$x=0-5$

$x=-5$

The point A is labeled at x=-5.

Case 2: x is 5 units more than 0.

$x=0+5$

$x=5$

The point B is labeled at x=5.

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Hatshy [7]

Answer:

52% probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: A puppy is adopted.

Event B: The puppy lives 7 or more years.

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This means that $P(A) = 0.65$

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This means that $P(B|A) = 0.8$

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$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(A)*P(B|A)$

$P(A \cap B) = 0.65*0.8$

$P(A \cap B) = 0.52$

52% probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

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Free_Kalibri [48]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Mice21 [21]

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