Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:

Compute the degrees of freedom as follows:


Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:


*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Answer:
50.8%
Step-by-step explanation:
That is the one my friend and I chose. It is 31/61 when all the stuff is added together and that is put to 50.8 as a percentage..
So
I=P⋅i⋅t=Ii⋅t=50000.04⋅6=20833.33
Answer:
f(x) = -3/7x - 6
Step-by-step explanation: