Question

Solve the following equation 4×6x−7=1 x= log8log6 x= log2log6 x= log6log8 x= log6log2

Answer 1

Answer:

The value of x is $x=\frac{\log(2)}{\log(6)}$.

Step-by-step explanation:

Solve the equation as follows:

$4\times 6^{x}-7=1$

     $4\times 6^{x}=7+1$

           $6^{x}=\frac{8}{4}$

           $6^{x}=2$

Take log on both sides.

$\log(6^{x})=\log(2)$

$x\log (6)=\log(2)$

        $x=\frac{\log(2)}{\log(6)}$

Thus, the value of x is $x=\frac{\log(2)}{\log(6)}$.