Answer:
24
Step-by-step explanation:
Problems at start = 32
-Problems done Friday = ¼ × 32 = <u> 8</u>
Problems still to be done = 24
Andrea had to do 24 problems on Saturday to complete the homework.
A)We have been given →
Hieght of trough = 5m
length of trough = 6m
Breadth of trough = 4m
so , As the top is opened for feeding animals.
Area of base = length× Breadth
= (6×4) m²
= 24 m²
Area of Front and back face = Hieght × length
= (5×6) m²
= 30m²
Area of side faces = hieght × Breadth
= (5×4) m²
= 20 m²
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B)Total Surface area of trough will be given by formula - 2(lb+bh+hl)
= 2{(6×4)+(4×5)+(5×6)}
= 2{24+20+30}
= 2×74
= 148 m²
As we have been told top is open , so we will deduct top from Total surface Area to obtain Surface area →
(148-24) m²
(Area of top will be same as base area , that is 24m² as we have solved in A)
= 124m²
Answer→ Surface area of trough is 124m²
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Answer:
The graph is a horizontal shift of the function two units to the left.
Step-by-step explanation:
The graph is a horizontal shift of the function two units to the left.
Remember that horizontal shifts appear as additions of a constant "c" to the x-coordinate inside the function. When the constant is negative the shift is to the right in |c| units, and when the constant is positive (like in this case) the shift is to the left in |c| units.
Answer:
- g(2.95) ≈ -1.8; g(3.05) ≈ -0.2
- A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.
Step-by-step explanation:
(a) The linear approximation of g(x) at x=b will be ...
g(x) ≈ g'(b)(x -b) +g(b)
Using the given relations, this is ...
g'(3) = 3² +7 = 16
g(x) ≈ 16(x -3) -1
Then the points of interest are ...
g(2.95) ≈ 16(2.95 -3) -1 = -1.8
g(3.05) ≈ 16(3.05 -3) -1 = -0.2
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(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)