Find the approximate surface to area to volume ratio of a softball with a radius of 2inches
1 answer:
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Answer:
Step-by-step explanation:
There is not much that can be done to figure out how to write 0.8 as a fraction, except to literally use what the decimal portion of your number, the .8, means.
Since there are 1 digits in 8, the very last digit is the "10th" decimal place.
So we can just say that .8 is the same as 8/10.
The fraction is not reduced to lowest terms. We can reduce this fraction to lowest terms by dividing both the numerator and denominator by 2.
Why divide by 2? 2 is the Greatest Common Divisor (GCD) or Greatest Common Factor (GCF) of the numbers 8 and 10.
So, this fraction reduced to lowest terms is 4/5
So your final answer is: 0.8 can be written as the fraction 8/10 simplified to 4/5
<em>Acceleration (a) = 5.1 m/s</em>²
<em>Initial speed (u) = 16 km/h </em>⇒
<em>m/s </em>≈ <em>4.5m/s</em><em>
</em><em>Final speed (v) =118 km/h </em>⇒
<em>m/s</em> ≈ <em>32.8m/s</em><em>
</em>
Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS
<em>So, When all quantities are in S.I. unit then,
</em>putting the values in the equation of motion,
<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>
Putting values in derived equation,
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em><em>
The total distance covered in that given condition is approx. 103.289 m.</em>
<em>Initial speed (u) = 16 km/h </em>⇒
</em><em>Final speed (v) =118 km/h </em>⇒
</em>
Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS
<em>So, When all quantities are in S.I. unit then,
</em>putting the values in the equation of motion,
<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>
Putting values in derived equation,
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S = </em>
⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em><em>
The total distance covered in that given condition is approx. 103.289 m.</em>