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Stolb23 [73]
3 years ago
5

Consider two persons. The age of one persoon isestimated between 25 and 35. The age of the other person isestimated between 15 a

nd 20. What is the estimated sum of thetwo persons? How much older is the first person?
Mathematics
1 answer:
Andrei [34K]3 years ago
7 0

Answer:

Q1. The estimated sum of the two people are between 40 and 55 years old.

Q2. The first person is between 10 and 15 years older.

Step-by-step explanation:

We are given Age Range's for 2 people. The first question is asking for the sum of the two people's ages. In this case we can just <u><em>add</em></u> the two minimum ages together and then the two maximum ages like so,

<u>min:</u> 25 + 15 = 40

<u>max:</u> 35 + 20 = 55

So the estimated sum of the two people are between 40 and 55 years old.

The second question asks how much older the First person is from the Second person. We can calculate this by <u><em>subtracting</em></u> both age ranges like so,

<u>min:</u> 25 - 15 = 10

<u>max:</u> 35 - 20 = 15

So the first person is between 10 and 15 years older.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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The proprietor of a boutique in New York wanted to determine the average age of his customers. A random sample of 25 customers r
jolli1 [7]

Answer:

28-2.064\frac{10}{\sqrt{25}}=23.872    

28+2.064\frac{10}{\sqrt{25}}=32.128    

So on this case the 95% confidence interval would be given by (23.9;32.1)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=28 represent the sample mean

\mu population mean (variable of interest)

s=10 represent the sample standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=25-1=24

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,24)".And we see that t_{\alpha/2}=2.064

Now we have everything in order to replace into formula (1):

28-2.064\frac{10}{\sqrt{25}}=23.872    

28+2.064\frac{10}{\sqrt{25}}=32.128    

So on this case the 95% confidence interval would be given by (23.9;32.1)    

7 0
3 years ago
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