You are trying to find out how much granola is needed for 1/6 of a recipe. To do this, you have to find 1/6 of the amount of granola needed for a whole recipe, which is 7/9.
So, you would multiply 1/6 * 7/9 = 7/54.
7/54 cannot be simplified, so your final answer is that you would need 7/54 of a cups of granola if you were going to make 1/6 of the recipe.
There are 10 sides becuase the equation set up is
and equal it to 144.
Solve for n and get 10
Let
A( 5.0,2.8) B( -2.8,5.1)
we know that
The formula to find the distance between two points is equal to
![d=\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%20%2B%28x2-x1%29%5E%7B2%7D%7D)
substitute in the formula
![d=\sqrt{(5.1-2.8)^{2} +(-2.8-5)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285.1-2.8%29%5E%7B2%7D%20%2B%28-2.8-5%29%5E%7B2%7D%7D)
![d=\sqrt{(2.3)^{2} +(-7.8)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%282.3%29%5E%7B2%7D%20%2B%28-7.8%29%5E%7B2%7D%7D)
![d=\sqrt{66.13}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B66.13%7D)
![d=8.13\ cm](https://tex.z-dn.net/?f=d%3D8.13%5C%20cm%20)
therefore
<u>the answer is</u>
the distance between these points is ![8.13\ cm](https://tex.z-dn.net/?f=8.13%5C%20cm)
Answer:
The median and IQR
Step-by-step explanation:
Hope it helps
Answer:
![4ft *\frac{12in}{1 ft}= 48 in](https://tex.z-dn.net/?f=%204ft%20%2A%5Cfrac%7B12in%7D%7B1%20ft%7D%3D%2048%20in)
Now since we have the same units for the scale model and the real one we can find the scale factor like this:
![Scale = \frac{48 in}{6in}= 8](https://tex.z-dn.net/?f=%20Scale%20%3D%20%5Cfrac%7B48%20in%7D%7B6in%7D%3D%208)
And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model
Step-by-step explanation:
For this problem we know that the scale model had a widthof 6 inches. And the actual model has a width of 4ft. First we need to convert the 4ft to inches and we got:
![4ft *\frac{12in}{1 ft}= 48 in](https://tex.z-dn.net/?f=%204ft%20%2A%5Cfrac%7B12in%7D%7B1%20ft%7D%3D%2048%20in)
Now since we have the same units for the scale model and the real one we can find the scale factor like this:
![Scale = \frac{48 in}{6in}= 8](https://tex.z-dn.net/?f=%20Scale%20%3D%20%5Cfrac%7B48%20in%7D%7B6in%7D%3D%208)
And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model