Answer:
(2 * L)+(2 * W)
Step-by-step explanation:
Slope=rise/run or changeiny/changeinx or (y2-y1)/(x2-x1) or (y1-y2)/(x1-x2)
so
pick any 2 points
(x,y)
(0,17) and (1,23)
slope=(y2-y1)/(x2-x1)
so
(23-17)/(1-0)=6/1=6
slope is 6
It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20
Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
∠A+∠B=180°
∠A=180°-54°
∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit
Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76°
Answer:
432 in^2
Step-by-step explanation:
in similar quadrilaterals, the first point of one quad. corresponds to the first point of the other quad, so in this case UA corresponds with CH.
since CH is 3/4 the length of UA, we can also assume that the other sides in ZUCH are 3/4 the length of their corresponding sides in SQUA.
even though we don't know what quadrilateral SQUA and ZUCH are, we know the area of SQUA is 9/16 times less than ZUCH.
want some proof?
lets say SQUA and ZUCH are rectangle/square
ZUCH: 4X4 = 16
SQUA: 3X3 = 9
now lets say they are trapezoids. We will set ZUCH 2nd base to 8 and height to 16, therefore SQUA bases will be 3 and 6, and the height will be 12 (multiply ZUCH lengths by 3/4)
ZUCH = (b1+b2)(h)/2 = (4+8)(16)/2 = 96
SQUA = (b1+b2)(h)/2 = (3+6)(12)/2 = 54
simplify 96/54 = 16/9
now we can multiply 243 by our factor 16/9 to find the area of SQUA.
243 * 16/9 = 432 in^2
