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Oksanka [162]
3 years ago
15

Which of these are qualdrilateral

Mathematics
2 answers:
Sholpan [36]3 years ago
7 0

Answer:

any four sided closed shape

Step-by-step explanation:

can you add the option?

Aleonysh [2.5K]3 years ago
6 0

Answer:

Square, Rectangle, Rhombus, Trapezoid, Parallelogram.

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Calculate all of this please and you will get the brainlist
ddd [48]

Answer:

4. 118 kg

w = 450 j ,  d = 3.8 m

w = mgh ⇒mg = w / h ⇒m = 450/3.8 = 118 kg

5. 9806.65 Joules

6. 25 J

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3 years ago
The Jones family spends $600 per month on groceries for their family. If this is 15% of their monthly budget, then what is their
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Step-by-step explanation:

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3 years ago
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Measuring the height of a tree is usually more difficult than measuring the diameter of the tree. Therefore, many researchers us
LenKa [72]

Answer:

(B) (0.396, 1.712)

Step-by-step explanation:

From the information given;

Confidence Interval = 0.95

Significance Level = 1 - 0.95 = 0.05

The confidence interval for regression coefficient beta (whereby in this case it is the coefficient of the diameter) is expressed by:

= ( Beta ^- \ t_{n-2}, \alpha/2 ( S.E \ of \ \^ \ \ ), Beta^+ \ t_{n-2}, \alpha/2 ( S.E \ of \ \^ \ \ ))

From the regression coefficient, the estimated value of beta^  = 1.054

= (1.054 - t_{29,0.025} *(0.322), 1.054 + t_{29,0.025}*(0.322))

t_{229,0.025} = 2.0452\\\\ = \mathbf{(0.396, 1.712)}

8 0
3 years ago
HELP<br> find the solution set of the inequality 15x-4 &lt; 29.
seropon [69]

Answer: is actually 15×4 is 60 and 60 is greater than 29

Step-by-step explanation:

6 0
3 years ago
University dean is interested in determining the proportion of students who receive some sort offinancial aid. rather than exami
vladimir2022 [97]
The confidence interval is
0.59\pm0.081

We first find p, our sample proportion.  118/200 = 0.59.

Next we find the z-score associated with this level of confidence:
Convert 98% to a decimal: 98% = 98/100 = 0.98
Subtract from 1:  1-0.98 = 0.02
Divide by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 2.33.

The margin of error (ME) is given by
ME=z\sqrt{\frac{p(1-p)}{n}}&#10;\\&#10;\\=2.33\sqrt{\frac{0.59(1-0.59)}{200}}=2.33\sqrt{\frac{0.2419}{200}}\approx0.081

This gives us the confidence interval 
0.59\pm0.081
8 0
3 years ago
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