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3 years ago

The square root of 49 is how much less than four squared

Mathematics

2 answers:

Paul [167]3 years ago

5 0

The answer is 9
sqrt(49) = 7
4^2 = 16
16-7 = 9

DIA [1.3K]3 years ago

4 0

The answer is 9
sqrt(49) = 7
4^2 = 16
<span>16-7 = 9</span>

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What is the perimeter, in feet, a rectangle whose length is twice its width and whose width is 8 feet?

anyanavicka [17]

If the width is 8ft and the length is twice the width then multiply 8 by 2 to find your length

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3 years ago

Andre received $60 for his birthday and put it in his piggy bank. Each week, he puts 3 more dollars in his bank. The amount of m

My name is Ann [436]

96 → B

substitute w = 12 into the equation D = 3w + 60

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3 years ago

The answer to all of these word problem

user100 [1]

Answer:Hope this helps!

Number 1 = 2 and 1/8

Number 2 = 6 and 3/40

Number 5 = 4 and 2/6

Number 6 = 15 and 1/3

Step-by-step explanation:

3 0

3 years ago

HighTech Inc. randomly tests its employees about company policies. Last year in the 560 random tests conducted, 26 employees fai

Tanzania [10]

Answer:

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

560 random tests conducted, 26 employees failed the test. This means that $n = 560, \pi = \frac{26}{560} = 0.046$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.33$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 - 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.025$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 + 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.067$

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

5 0

4 years ago

George walks 1 mile to school. He leaves home at the same time each day, walks at a steady speed of 3 miles per hour, and arrive

alex41 [277]

Answer:

George must run the last half mile at a speed of 6 miles per hour in order to arrive at school just as school begins today

Step-by-step explanation:

Here, we are interested in calculating the number of hours George must walk to arrive at school the normal time he arrives given that his speed is different from what it used to be.

Let’s first start at looking at how many hours he take per day on a normal day, all things being equal.

Mathematically;

time = distance/speed

He walks 1 mile at 3 miles per hour.

Thus, the total amount of time he spend each normal day would be;

time = 1/3 hour or 20 minutes

Now, let’s look at his split journey today. What we know is that by adding the times taken for each side of the journey, he would arrive at the school the normal time he arrives given that he left home at the time he used to.

Let the unknown speed be x miles/hour

Mathematically;

We shall be using the formula for time by dividing the distance by the speed

1/3 = 1/2/(2) + 1/2/x

1/3 = 1/4 + 1/2x

1/2x = 1/3 - 1/4

1/2x = (4-3)/12

1/2x = 1/12

2x = 12

x = 12/2

x = 6 miles per hour

4 0

3 years ago