You aren't sharing much information (no directions??).
If your triangle is a right triangle AND 5x-1 and 4x+1 represent the lengths of the 2 shortest sides, then the Pyth. Theorem tells us that
(5x-1)^2 + (4x+1)^2 = (hypotenuse length)^2.
We know that this could not be an equilateral triangle, because 5x-1 differs from 4x+1.
This could be an isosceles triangle if the third side were either 5x-1 or 4x+1.
Please be more specific about what you're supposed to do here.
The slope of a straight line which is parallel to X axis is always equal to 0 (zero).
Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.


Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as

by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because

is a polynomial).
Answer:
Step-by-step explanation:
Answer:
To work out the percentage, all you have to do is divide the first subject by the second and multiply that by 100%.
In other words, 
= 
=
.
Step-by-step explanation:
Hope this helped!