Answer:
Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i
Step-by-step explanation:
( ± ) / = (
x1= 2+i
x2= 2-i
( ± ) / = (-6 ± )/4= (-3 ± i)/2
x1 = -3/2 +i
x2 = -3/2 -i
Answer:
<h2>
68 feet.</h2>
Step-by-step explanation:
At maximum height, the velocity of the flare will be zero.
If the flare height above the ground is modeled by the equation
h = -16t²+64t+4
Velocity = dh/dt = 0
-32t + 64 = 0
-32t = -64
t = -64/-32
t = 2secs
This shows that the flare reaches its maximum height after 2secs.
To get the maximum height of the flare, we will substitute t = 2s into the equation h = -16t²+64t+4
h = -16(2)² + 64(2)+4
h = -64+128+4
h = 64+4
h = 68 feet
The maximum height of the flare is 64 feet.
Answer:
4
Step-by-step explanation:
Answer:
2(x-10)/(x+10)(x-4)
Step-by-step explanation:
Find the complete question attached as a diagram
Given the following
F(x) = x-16/x²+6x-40
Factoring the denominator
F(x) = x-16/x²-4x+10x-40.
F(x) = x-16/x(x-4)+10(x-4)
F(x) = x-16/(x+10)(x-4)
g(x) = 1/x+10
Adding both functions
F(x)+g(x) = x-16/(x+10)(x-4) + 1/x+10.
F(x)+g(x) = x-16+(x-4)/(x+10)(x-4)
F(x)+g(x) = x-16+x-4/(x+10)(x-4)
F(x)+g(x) = x+x-16-4/(x+10)(x-4)
F(x)+g(x) = 2x-20/(x+10)(x-4)
F(x)+g(x) = 2(x-10)/(x+10)(x-4)