Answer:
30° = m∠GFH
Step-by-step explanation:
Since ∠EFH and ∠GFH are complementary, the sum of their measures i 90.
Let x = m∠GFH
2x = m∠EFH
m∠GFH + m∠EFH = 90
x + 2x = 90
3x = 90
x = 30° = m∠GFH
Answer:
a = ln 35
Step-by-step explanation:
Given e^a = 35, take the natural log of both sides, obtaining:
ln e^a = ln 35. Recall that ln e^x = x, which means that ln e^a = a.
Then a = ln 35.
Next time, please share the answer choices!
<span>a.
The radius of earth is about 6400 kilometers. Find the circumference of
a great circle.
Circumference = 2π(radius) = 2π(6400 km) = 40.212,39 km
b. Write an equation for the circumference of any
latitude circle with angle theta
As stated, </span><span><span>the
length of any parallel of latitude (this is the circumference of corresponding circle) is equal to the circumference of a
great circle of Earth times the cosine of the latitude angle</span>:
=> Circumference = 2π*radius* cos(Θ) = 2 π*6400km*cos(Θ) = 40,212.39 cos(Θ)
Answer: circumference = 40,212.39 cos(Θ) km
c. Which latitude circle has a
circumference of about 3593 kilometers?
Make </span><span><span>40,212.39 cos(Θ)</span> km = 3593 km
=> cos(Θ) = 3593 / 40,212.39 = 0.08935 => Θ = arccos(0.08935) = 84.5° = 1.48 rad
Answer: 1.48
d. What is the circumference of
the Equator?
</span>
For the Equator Θ = 0°
=> circumference = 40,213.49cos(0°) km = 40,212.49 km
Answer: 40,212.49 km
1: 14 ft
2: 18
3: 11; 28
4: 8; 96
5: a = 5x3
6: a = 8x8
7: 1x42, 2x21, 3x14, and 6x7. 6x7 probably makes the most sense.
