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3 years ago

In which case would it be most appropriate to use feet as a unit of measurement?

2 answers:

8 0

In which case would it be most appropriate to use feet as a unit of measurement? C. height of a door

The length of length of a paper clip and the width of an eyelash would be too small. It could not be measured by feet. The distance from Chicago to San Francisco would be too long and should be measured by miles.

I hope this helps! :)
~ erudite

il63 [147K]3 years ago

3 0

A height of a door because the distance from Chicago to San Francisco would be expressed as miles and the width of an eyelashes would be millimeters and the lenght of a paperclip would be centimerters.

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Someone please answer.

lutik1710 [3]

Answer:

I don't no sorry for that

3 0

3 years ago

What is the area of the trapezoid?

Maslowich

<h3>Given Information :</h3>

Length of parallel sides = 60 ft and 40 ft
Height of the trapezoid = 30 ft

<h3>To calculate :</h3>

Area of the trapezoid.

<h3>Calculation :</h3>

As we know that,

$\bigstar \: \boxed{\sf {Area_{(Trapezium)} = \dfrac{1}{2} \times ( a + b) \times h}} \\$

a and b are length of parallel sides.
h denotes height.

Substituting values, we get :

$\longmapsto$ Area = $\sf \dfrac{1}{2}$ × ( 60 + 40 ) × 30 ft $\sf ^2$

$\longmapsto$ Area = $\sf \dfrac{1}{2}$ × 100 × 30 ft $\sf ^2$

$\longmapsto$ Area = 1 × 100 × 15 ft $\sf ^2$

$\longmapsto$ Area = 100 × 15 ft $\sf ^2$

$\longmapsto$ Area = 1500 ft $\sf ^2$

Therefore,

Area of the trapezoid is 1500 ft $\sf ^2$

6 0

3 years ago

HEYOO PEEPS PUT THIS INTO YOUR OWN WORDS Depends on the mass and force acting on it.

makkiz [27]

Answer:

Mass and force acting on it determine how it ...

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Anyone please could help

Shalnov [3]

The answer would be c.127

5 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago